MPM2D Review Quiz 1

Given the function

 $y=3\left(x-2\right)^2+1$  
the vertex is located at:

• (-2,1)

• (3,2)

• (3,1)

• (2,1)

A line that is perpendicular to

 $y=3x-4$  with a y-intercept of 2 is:

•  $y=-3x+2$  

•  $y=\frac{1}{3}x+2$  

•  $y=-\frac{1}{3}x+2$  

•  $y=-\frac{1}{3}x-2$  

The parent function moved two units right, four units down and compressed by a factor of 0.5 is:

• $y=-\frac{1}{2}\left(x+2\right)^2-4$

• $y=\frac{1}{2}\left(x-2\right)^2-4$

• $y=-\frac{1}{2}\left(x-2\right)^2-4$

• $y=\frac{1}{2}\left(x-4\right)^2+2$

The point of intersection of

 $y=3x-1\ and\ 2y=6x-2$  is at:

• (0,0)

• (3,-1)
  

• There is no point of intersection as they are parallel

• These are the same line

In order to solve for the angle E, we should use:

• SOH (sine)

• CAH (cosine)

• TOA (tangent)

• Any of the above

In order to solve for Angle B, we would need to use:

• SOH (Sine)

• CAH (Cosine)

• TOA (Tangent)

• Any of the above.

The triangles shown are:

• Similar

• Congruent

• Equilateral

• None of the above

The length of

 $\overline{EF}$  is:

• 12

• 10

• 24

• 18

The equation that matches the quadratic shown is:

• $y=\left(x+1\right)\left(x+3\right)$

• $y=2\left(x+3\right)\left(x+1\right)$

• $y=2\left(x-3\right)\left(x-1\right)$

• $y=\left(x-1\right)\left(x-3\right)$

When expanded and simplified,

 $y=\frac{1}{2}\left(x+4\right)\left(x-4\right)$  is:

•  $y=\frac{1}{2}x^2+4x-8$  

•  $\frac{1}{2}x^2+8$  

•  $\frac{1}{2}x^2-4x-8$  

• None of the above