
机械振动-2.弹簧组合
Authored by 洪福孝Ang How
Physics
10th - 12th Grade
Used 2+ times

AI Actions
Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...
Content View
Student View
8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,则弹簧组合为a联,其等效劲度系数为b:
a:串联, b=300N/m
a:串联, b=200/3 N/m
a:并联, b=300N/m
a:并联, b=200/3 N/m
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,并悬挂一重物G=20N,则弹簧组合的总伸长量为:(弹簧本身的质量不计)
0.3m
3m
0.067m
0.67m
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,并悬挂一重物G=20N,则弹簧A伸长量为:(弹簧本身的质量不计)
0.067m
0.1m
0.2m
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
将劲度系数、质量皆相同的弹簧以不同的方式组合,如上图。若悬挂上相同的重物(load),则上述的弹簧组合中有最大总伸长量的组合为:
A
B
C
D
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
已知弹簧甲的劲度系数k1=100N/m, 弹簧乙的劲度系数k2=400N/m, 以上图的方式组合,则弹簧甲,乙是以什么方式组合?其等效劲度系数k=?
串联, k=500N/m
并联, k=500N/m
串联, k=80N/m
并联, k=80N/m
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
以两个完全相同的弹簧以不同方式组合,若要使其等效劲度系数变小,则弹簧应以什么方式组合?
串联
并联
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
将一劲度系数为k的弹簧剪切成3个相同长度的小弹簧,则每个小弹簧的劲度系数为多少?
k/3
3k
Access all questions and much more by creating a free account
Create resources
Host any resource
Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever
or continue with

Microsoft
%20(1).png)
Apple
Others
Already have an account?