Search Header Logo

机械振动-2.弹簧组合

Authored by 洪福孝Ang How

Physics

10th - 12th Grade

Used 2+ times

机械振动-2.弹簧组合
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,则弹簧组合为a联,其等效劲度系数为b

a:串联, b=300N/m

a:串联, b=200/3 N/m

a:并联, b=300N/m

a:并联, b=200/3 N/m

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,并悬挂一重物G=20N,则弹簧组合的总伸长量为:(弹簧本身的质量不计)

0.3m

3m

0.067m

0.67m

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

已知弹簧A的劲度系数KA=100N/m,弹簧B的劲度系数KB=200N/m. 若将弹簧A及弹簧B以上图方式组合,并悬挂一重物G=20N,则弹簧A伸长量为:(弹簧本身的质量不计)

0.067m

0.1m

0.2m

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

将劲度系数、质量皆相同的弹簧以不同的方式组合,如上图。若悬挂上相同的重物(load),则上述的弹簧组合中有最大总伸长量的组合为:

A

B

C

D

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

已知弹簧甲的劲度系数k1=100N/m, 弹簧乙的劲度系数k2=400N/m, 以上图的方式组合,则弹簧甲,乙是以什么方式组合?其等效劲度系数k=?

串联, k=500N/m

并联, k=500N/m

串联, k=80N/m

并联, k=80N/m

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

以两个完全相同的弹簧以不同方式组合,若要使其等效劲度系数变小,则弹簧应以什么方式组合?

串联

并联

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

将一劲度系数为k的弹簧剪切成3个相同长度的小弹簧,则每个小弹簧的劲度系数为多少?

k/3

3k

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?