Triangle proportionality theorem

Find the missing length.

• 21
• 18
• 16
• 24

Tags

CCSS.HSG.CO.C.9

Solve for x.

• 10

• 5

• 7

• 4

Tags

CCSS.HSG.SRT.B.4

Find the missing length.

• 35
• 28
• 42
• 13

Tags

CCSS.HSG.SRT.C.8

The Side Splitter Theorem states that If a line is parallel to one side of a triangle and intersects the other two sides, then  $\frac{AB}{BC\ }=\frac{AE}{?}$  What is the question mark?

• BE

• CD

• AD

• ED

Tags

CCSS.HSG.SRT.B.4

Solve for x.

• 9

• 8

• 5

• 7

Tags

CCSS.HSG.CO.C.9

Solve for x.

• 4

• 9

• 3

• 7

Tags

CCSS.HSG.CO.C.9

Find the value of x.

• x = 4.5
• x = 9
• x = 30
• x = 3

Tags

CCSS.HSG.SRT.B.4

• 1

• 2

• 3

• 4

Tags

CCSS.HSG.SRT.B.4

Use the converse of the side-splitter theorem to determine if   $TU\parallel RS$  . Which statement is true?

• Line segment TU is parallel to line segment RS because  $\frac{32}{36}=\frac{40}{45}$   .

• Line segment TU is not parallel to line segment RS because  $\frac{32}{36}\ne\frac{40}{45}$  

• Line segment TU is parallel to line segment RS because  $\frac{32}{45}=\frac{40}{36}$   .

• Line segment TU is not parallel to line segment RS because  $\frac{32}{45}\ne\frac{40}{36}$   .

Tags

CCSS.HSG.SRT.B.4

Line RS intersects triangle BCD at two points and is parallel to segment DC.

Which statements are correct? Select three options.

• △BCD is similar to △BSR.

• $\frac{BR}{RD}=\frac{BS}{SC}$

• If the ratio of BR to BD is $\frac{2}{3}$ , then it is possible that BS = 6 and BC = 3.

• (BR)(SC) = (RD)(BS)

• $\frac{BR}{RS}=\frac{BS}{SC}$

Tags

CCSS.HSG.SRT.B.4