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HW 3.6 Conditional Probability

Authored by Ashlynn Hardin

Mathematics

10th Grade

CCSS covered

Used 10+ times

HW 3.6 Conditional Probability
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Conditional probability is...

to find the P of BOTH events occurring together

to find the P of one event OR another event occurring

to find the P of ONE event

to find the P of one event GIVEN another event

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.B.6

CCSS.HSS.CP.A.2

CCSS.HSS.CP.A.4

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find P(tails | rolling a 3)

612\frac{6}{12}

126\frac{12}{6}

112\frac{1}{12}

26\frac{2}{6}

Answer explanation

P(A and B)P(B)\frac{P\left(A\ and\ B\right)}{P\left(B\right)}

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.B.6

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find P(tails and rolling a 3)

612\frac{6}{12}

126\frac{12}{6}

112\frac{1}{12}

26\frac{2}{6}

Answer explanation

where do tails and 3 intersect?

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.CP.A.2

CCSS.HSS.CP.B.8

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find P(Clash of clans | among us)

 261555\frac{261}{555}  

 261376\frac{261}{376}  

 376261\frac{376}{261}  

 127261\frac{127}{261}  

Answer explanation

 P(A and B)P(B)\frac{P\left(A\ and\ B\right)}{P\left(B\right)}  

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.B.6

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find P(Adult AND skittles)

 27194\frac{27}{194}  

 104194\frac{104}{194}  

 110194\frac{110}{194}  

 83194\frac{83}{194}  

Answer explanation

Where do adults and skittles meet?

Tags

CCSS.HSS.CP.A.1

CCSS.HSS.ID.B.5

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Find P(M&M | kid)

 7194\frac{7}{194}  

 90194\frac{90}{194}  

 790\frac{7}{90}  

Answer explanation

 P(A and B)P(B)\frac{P\left(A\ and\ B\right)}{P\left(B\right)}  

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.B.6

CCSS.HSS.CP.A.4

CCSS.HSS.ID.B.5

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the correct conditional Probability formula?

P(A)×P(B)P\left(A\right)\times P\left(B\right)

P(A and B)P(B)\frac{P\left(A\ and\ B\right)}{P\left(B\right)}

P(B)P(A and B)\frac{P\left(B\right)}{P\left(A\ and\ B\right)}

P(A)+P(B)P\left(A\right)+P\left(B\right)

Tags

CCSS.HSS.CP.A.3

CCSS.HSS.CP.B.8

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