Solving Polynomial Equations

Solve by Factoring:  4x² + 11x - 3 = 0

• x = -3/4 and x = -1
• x = 4 and x = 3
• x = 1/4 and x = -3
• x = -1/4 and x = 3

Tags

CCSS.HSA-REI.B.4B

Solve by Factoring:
x² + 15x + 64 = 20

• {-8, 2}
• {-7, 5}
• {-11, -4}
• {-11}

Tags

CCSS.HSA-REI.B.4B

Solve x⁴ - 256 = 0

• x = 4, x = - 4
• x = 4, x = 4i
• x = 4, x -4, x = 4i
• x = 4, x -4, x = 4i,         x = -4i

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

CCSS.HSN.CN.C.8

Find all zeros for the polynomial function P(x) = x³ -3x²-5x+15

• 3, √5 
• 3, √5, -√5
• -3, √5, -√5
• -3, 5i, -5i

Tags

CCSS.HSA.APR.B.3

CCSS.HSN.CN.C.9

Find all zeros of the polynomial function P(x) = x³+6x²+9x+54

• 6, 3, -3
• -6, 3, -3
• -6, 3i, -3i
• 6, 3i, -3i

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Solve (x²-9) = 0

• x = 9

• x = 9, -9

• x = 3, -3

• x = 3

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

Solve the following equation. x⁴ + 4x³ + 3x² = 0

• x = 0, x = 3, x = 1

• x = -3, x = -1

• x = 3, x = 1

• x = 0, x = -3, x = -1

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

Tags

CCSS.HSA.REI.B.4

What are two solutions to the polynomial:
x²+14x=0

• x=0, x= 14
• x=-14
• x= 1, x =10
• x= -14, x = 0 

Tags

CCSS.HSA.REI.B.4

Solve: 2x²-14x+24 = 0

• x = 4, 3

• x = 9/2, 10/4

• x = -3, -4

• x = -9/2, -10/4

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4