Exponential Growth & Decay

Exponential Growth & Decay

9th - 12th Grade

12 Qs

quiz-placeholder

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Exponential Growth & Decay

Exponential Growth & Decay

Assessment

Quiz

Mathematics

9th - 12th Grade

Practice Problem

Medium

CCSS
HSF-IF.C.8B, HSF.LE.A.2, HSF-LE.A.1C

Standards-aligned

Created by

Mr. Casilli

Used 7+ times

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12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Name the formula:

y = a(1 + r)t

Exponential Growth

Exponential Decay

Compound Interest

Continuously Compounded Interest

Tags

CCSS.HSF-IF.C.8B

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Name the formula:

y = a(1 - r)t

Exponential Growth

Exponential Decay

Compound Interest

Continuously Compounded Interest

Tags

CCSS.HSF-IF.C.8B

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Name the formula:

 A=P(1+rn)ntA=P(1+\frac{r}{n})^{nt}  

Exponential Growth

Exponential Decay

Compound Interest

Continuously Compounded Interest

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Name the formula:

 A=PertA=Pe^{rt}  

Exponential Growth

Exponential Decay

Compound Interest

Continuously Compounded Interest

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

In 2010, the population of Peabody was 54, 894. If the population rose by an average of 2% each year since then, which equation models the population of Peabody in 2021?

Tags

CCSS.HSF.LE.A.2

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

In 2015, there were 5,897 computer viruses in Jenna's computer. Each year after, the number of viruses increased by about 73%. How many computer viruses are there currently running loose in Jenna's computer in 2021?

Tags

CCSS.HSF-LE.A.1C

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Nick saves up $7500 and uses it to purchase a new jet ski. Unfortunately, his jet ski depreciates 18% in value every year that he owns it. How much will Nick's jet ski be worth in 3 years?

 A = 7,500e(.183)A\ =\ 7,500e^{\left(.18\cdot3\right)} 

 A = 7,500(1+.2812)(123)A\ =\ 7,500\left(1+\frac{.28}{12}\right)^{\left(12\cdot3\right)} 

 A = 7,500(1+.18)3A\ =\ 7,500\left(1+.18\right)^3 

 A = 7,500(1.18)3A\ =\ 7,500\left(1-.18\right)^3 

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