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Implicit Differentiation Basic Practice

Authored by Adeyemi Aderinto

Mathematics

10th Grade - University

CCSS covered

Used 27+ times

Implicit Differentiation Basic Practice
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8 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx  if     4x + 12y = 10


 dydx=13\frac{dy}{dx}=-\frac{1}{3}  

 dydx=1x3y\frac{dy}{dx}=-\frac{1x}{3y}  

 dydx=31\frac{dy}{dx}=-\frac{3}{1}  

 dydx=13\frac{dy}{dx}=\frac{1}{3}  

Tags

CCSS.HSA.CED.A.4

CCSS.HSA.REI.A.1

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if     -7x + 9y = 12

dydx=79\frac{dy}{dx}=\frac{7}{9}

dydx=199\frac{dy}{dx}=\frac{19}{9}

dydx=79\frac{dy}{dx}=-\frac{7}{9}

dydx=199\frac{dy}{dx}=-\frac{19}{9}

 dydx=97\frac{dy}{dx}=\frac{9}{7} 

Tags

CCSS.HSA.CED.A.4

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if     4x2+5y2=94x^2+5y^2=9  

 dydx=4x5y\frac{dy}{dx}=-\frac{4x}{5y}  

 dydx=4y5x\frac{dy}{dx}=-\frac{4y}{5x}  

 dydx=4x5y\frac{dy}{dx}=\frac{4x}{5y}  

 dydx=5x4y\frac{dy}{dx}=-\frac{5x}{4y}  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate w.r.t x if     8x2+12y2=24-8x^2+12y^2=24  

 dydx=2x3y\frac{dy}{dx}=\frac{2x}{3y}  

 dydx=2x3y\frac{dy}{dx}=-\frac{2x}{3y}  

 dydx=3x2y\frac{dy}{dx}=\frac{3x}{2y}  

 dydx=3x2y\frac{dy}{dx}=-\frac{3x}{2y}  

 dydx=3y2x\frac{dy}{dx}=\frac{3y}{2x}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if     7x3+4y3 = 10-7x^3+4y^3\ =\ 10  

 dydx=7x4y\frac{dy}{dx}=\frac{7x}{4y}  

 dydx=7x24y2\frac{dy}{dx}=\frac{7x^2}{4y^2}  

 dydx=7x34y3\frac{dy}{dx}=\frac{7x^3}{4y^3}  

 dydx=7x24y2\frac{dy}{dx}=-\frac{7x^2}{4y^2}  

Tags

CCSS.HSA.APR.A.1

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if      3x26y3=133x^2-6y^3=13  

 dydx=x3y2\frac{dy}{dx}=\frac{x}{3y^2}  

 dydx=x3y2\frac{dy}{dx}=-\frac{x}{3y^2}  

 dydx=18x6y2\frac{dy}{dx}=\frac{18x}{6y^2}  

 dydx=3xy2\frac{dy}{dx}=-\frac{3x}{y^2}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if        3x25x+6y27y=243x^2-5x+6y^2-7y=24  

 dydx=6x+512y7\frac{dy}{dx}=\frac{-6x+5}{12y-7}  

 dydx=6x+512y+7\frac{dy}{dx}=\frac{-6x+5}{-12y+7}  

 dydx=6x512y7\frac{dy}{dx}=\frac{6x-5}{12y-7}  

 dydx=3x+56y7\frac{dy}{dx}=\frac{-3x+5}{6y-7}  

 dydx=3x56y7\frac{dy}{dx}=\frac{3x-5}{6y-7}  

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