Radicals Quiz 1/29

FULLY Simplify  $\sqrt{200}$  .

•  $2\sqrt{10}$   

•  $10\sqrt{2}$ 

•  $20$  

•  $5\sqrt{10}$  

FULLY Simplify $\frac{\sqrt{16}}{\sqrt{8}}$ . 

•  $\sqrt{2}$  

•  $\frac{4}{\sqrt{8}}$  

•  $\frac{1}{\sqrt{2}}$  

•  $2\sqrt{2}$  

FULLY Simplify $2\sqrt{5}\cdot3\sqrt{5}$ .

•  $6\sqrt{25}$  

•  $30$  

•  $10\sqrt{15}$  

•  $6\sqrt{5}$  

Solve for x:

 $\sqrt{3}\cdot x=6$ . 

(HINT: Isolate x by doing the OPPOSITE operation)

•  $x=\frac{6}{\sqrt{3}}$  

•  $x=2\sqrt{3}$  

•  $x=\frac{6\sqrt{3}}{3}$  

•  $x=6$  

FULLY Simplify $3\sqrt{60}$ .

•  $6\sqrt{15}$  

•  $2\sqrt{15}$  

•  $5\sqrt{15}$  

•  $3\sqrt{15}$  

FULLY Simplify $\frac{15}{\sqrt{5}}$ .

•  $\sqrt{3}$  

•  $3\sqrt{5}$  

•  $15\sqrt{5}$  

•  $\frac{\sqrt{5}}{\sqrt{5}}$  

FULLY Simplify  $\left(3\sqrt{6}\right)^2$ .

•  $9\sqrt{36}$  

•  $54$  

•  $6\sqrt{12}$  

•  $9\sqrt{6}$  

When finding the prime factorization for 1000 using factor trees, Student A made the first two branches 10 and 100. Student B made the first two branches 16 and 62.5. Who is correct?

• Student A

• Student B

• Both are correct

• Neither are correct

For the problem,

 $5\sqrt{12}\cdot7\sqrt{8}$ , Student A simplified the two radicals FIRST and then multiplied. Student B multiplied (outside x outside and inside x inside) FIRST and then simplified the radical. Who is correct?

• Student A

• Student B

• Both are correct

• Neither are correct

Which would make THE MOST SENSE to multiply the fraction by in order to rationalize the denominator?

 $\frac{2}{\sqrt{7}}$ .

•  $\frac{\sqrt{7}}{\sqrt{7}}$  

•  $\frac{1}{\sqrt{7}}$  

•  $\frac{2}{2}$  

•  $\sqrt{7}$