3.2 Solving Quadratic Equations

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x + 2)(x - 3) = 0

• { 2, 3 }
• { -2, -3 }
• { 2, 3 }
• { -2, 3 }

Tags

CCSS.HSA-REI.B.4B

Solve by factoring

• -4, 2

• -2, 4

• -16

• -4

Tags

CCSS.HSA-REI.B.4B

Solve using the Quadratic Formula:

2x² + 2x − 12 = 0

• x = −2, 3

• x = 2, 3

• x = 2, −3

• x = −2, −3

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (HINT: Factor GCF 1st)

• x = 3, x = -6

• x = 0, x = 2

• x = 2, x = 3

• x = -2, x = 1

Tags

CCSS.HSA-REI.B.4B

 $2x^2=8x+3$ 

 

 $2x^2-8x-3=0$  

 $x=\frac{8\pm\sqrt{64-4\left(2\right)\left(-3\right)}}{4}$  

 $x=\frac{8\pm\sqrt{40}}{4}$ 

 $x=\frac{8\pm2\sqrt{10}}{4}$  

 $x=\frac{4\pm\sqrt{10}}{2}$  

Suzanne solved the equation using this process.

Did she make a mistake?

If yes, at which line did she make her first mistake?

(There are 5 steps in her process)

• Suzanne made no errors.
  

• Step 2
  

• Step 3
  

• Step 4
  

• Step 5
  

Tags

CCSS.HSA-REI.B.4B

Solve
x² + 13x + 12 = 0

• x = -12, -1
• x = 12, 1
• x = 13, 1
• x = -13, -1

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratic equation...

x² + 3x + 2 = 0

• x = -1

  x = -2

• x = 1

  x = 2

• x = -1

  x = 2

• x = 1

  x = -2

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratic equation...

x² + 9x + 20 = 0

• x = -2

  x = -10

• x = -5

  x = -4

• x = -1

  x = -20

• x = 4

  x = 5

Tags

CCSS.HSA-REI.B.4B

Solve by factoring:
 $x^2-36=0$ 

•  $x=\pm6$  

•  $x=\pm36$  

•  $x=\pm18$  

• No real solutions

Tags

CCSS.HSA-REI.B.4B