Chain rule

Chain rule

University

5 Qs

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Chain rule

Chain rule

Assessment

Quiz

Mathematics

University

Practice Problem

Medium

CCSS
HSA.APR.A.1, HSA.SSE.A.1, HSA.SSE.A.2

Standards-aligned

Created by

HALIMATUL BM

Used 13+ times

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5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find  dydx\frac{dy}{dx}  given that

 y=u5  and   u=x6+4y=u^5\ \ and\ \ \ u=x^6+4  

 dydx=5x5(x4+4)4\frac{dy}{dx}=5x^5(x^4+4)^4  

 dydx=6x5(x6+4)4\frac{dy}{dx}=6x^5(x^6+4)^4 

 dydx=30x5(x6+4)4\frac{dy}{dx}=30x^5(x^6+4)^4 

 dydx=30x6(x6+4)4\frac{dy}{dx}=30x^6(x^6+4)^4  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Given y=u2  and  u=x32xy=u^2\ \ and\ \ u=x^3-2x  . Find  dydx\frac{dy}{dx}  

6x5 - 12x3+8x

6x5 - 16x3+8x

x6-4x4+4x2

6x5 - 16x3-8x

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.A.2

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 dydx if y=(2x2+4)3\frac{dy}{dx}\ if\ y=\left(2x^2+4\right)^3  Find

 (12x+4)(2x2+4)2\left(12x+4\right)\left(2x^2+4\right)^2  

 3(2x2+4)23\left(2x^2+4\right)^2  

 12x(2x2+4)212x\left(2x^2+4\right)^2  

 12(2x2+4)212\left(2x^2+4\right)^2  

Tags

CCSS.HSA.APR.A.1

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find dydx\frac{dy}{dx}  if  y=u3   and  u=3x2x2y=u^3\ \ \ and\ \ u=3x-2x^2  

dy/dx = (3 - 4x)⋅3(3x - 2x2)2

dy/dx = 3(3x - 2x2)2

dy/dx = 3(3 - 4x)2

dy/dx = (3 - 4x)(9x - 18x2)2

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