Assumindo que log(2)= 0,3 e log(5)= 0,7 , então o log(20) é:

não é possível calcular, pois faltam dados.

Logaritmo

Authored by Suzana Freitas

Mathematics

10th Grade - University

Used 5+ times

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Aplicando a propriedade log $x^3$ + 5 log ( $y^2$ ), temos:

$x^3y^{10}$

log ( $x^3y^{10}$ )

$\frac{x^3}{y^{10}}$

log( $\frac{x^3}{y^{10}}$ )

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Aplicando a propriedade log $x^2$ - log $y$ temos:

$\frac{x^2}{y}$

log ( $\frac{x^2}{y}$ )

$x^2y$

log ( $x^2y$ )

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Qual das alternativas tem relação com o logaritmo $\log_38$

$8^3$

$\frac{\log\ 8}{\log\ 3}$

$3^8$

$\frac{8}{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Qual o valor do logaritmo $\log_2\left(\frac{1}{16}\right)$ ?

- 4

-8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Qual o valor de $\log_21$ ?

$\frac{1}{2}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Calcule $\log_2\left(16\right)^3$

$3$

$12$

$36$

$4$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Calcule Log 10000

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Qual o valor de $5\log_28-\log_381\div\log_39$

-13

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Logaritmo

Aplicando a propriedade log x3x^3x3 + 5 log ( y2y^2y2 ), temos:

Aplicando a propriedade log x2x^2x2 - log yyy temos:

Qual das alternativas tem relação com o logaritmo log⁡38\log_38log3​8

Qual o valor do logaritmo log⁡2(116)\log_2\left(\frac{1}{16}\right)log2​(161​) ?

Qual o valor de log⁡21\log_21log2​1 ?

Calcule log⁡2(16)3\log_2\left(16\right)^3log2​(16)3

Calcule Log 10000

Qual o valor de 5log⁡28−log⁡381÷log⁡395\log_28-\log_381\div\log_395log2​8−log3​81÷log3​9

O valor de Y = log132 132 – log5 1 é igual a :

Assumindo que log(2)= 0,3 e log(5)= 0,7 , então o log(20) é:

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Discover more resources for Mathematics

Aplicando a propriedade log $x^3$ + 5 log ( $y^2$ ), temos:

Aplicando a propriedade log $x^2$ - log $y$ temos:

Qual das alternativas tem relação com o logaritmo $\log_38$

Qual o valor do logaritmo $\log_2\left(\frac{1}{16}\right)$ ?

Qual o valor de $\log_21$ ?

Calcule $\log_2\left(16\right)^3$

Qual o valor de $5\log_28-\log_381\div\log_39$

O valor de Y = log₁₃₂ 132 – log₅ 1 é igual a :