review of exponents and logs

review of exponents and logs

10th - 11th Grade

25 Qs

quiz-placeholder

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review of exponents and logs

review of exponents and logs

Assessment

Quiz

Mathematics

10th - 11th Grade

Hard

CCSS
HSF.BF.B.5, HSF.LE.A.1, HSA.SSE.B.3

+17

Standards-aligned

Created by

Lynda Ezeneke

Used 71+ times

FREE Resource

25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image
Match the graph with its equation
y = log5 (x + 1) + 1 
y = log5 (x - 1) + 1 
y = log5 (x2) + 1 
y = log5 (x)-1

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSA.REI.D.11

CCSS.HSF.BF.B.5

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which graph matches the logarithmic equation

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which equation matches this graph?

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Which equation matches this graph?

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Write an equation that models the following situation:
Samantha's hair was known to grow very rapidly. It began at a length of 6 in and grew at a rate of 14% a week.
y=6(0.14)x
y=6(1+14)x
y=6(1.14)x
y=6(0.86)x

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.BF.A.1

CCSS.HSF.IF.B.4

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image
Is this exponential growth or decay?
Growth
Decay

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.B.5

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A population of 1500 deer decreases by 1.5% per year. At the end of 10 years, there will be approximately 1290 deer in the population.


Which function can be used to determine the number of deer, y, in this population at the end of t years?

y=1500(10.015)ty=1500(1-0.015)^t

y=1500(0.015)ty=1500(0.015)^t

y=1500(1+0.015)ty=1500(1+0.015)^t

y=1500(1.5)ty=1500(1.5)^t

Tags

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

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