Intercept Form

What is another way to say "where a function crosses the x-axis"?

• x-intercept

• zero

• root

• all of these.

• solution

Tags

CCSS.HSF-IF.C.7C

What does intercept form of a quadratic equation look like?

• y=ax²+bx+c

• y=a(x-h)²+k

• y=a(x-p)(x-q)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Find the roots and a point on the quadratic, then find the intercept form for each quadratic.

• y=(x-5)(x-1)

• y=(x+5)(x+1)

• y=x² +6x+5

• y=2(x-5)(x-1)

What is the equation for the graph in intercept form?

• y = -2(x-5)(x-3)

• y = - (x-5)(x-3)

• y = - (x+5)(x+3)

• y = - x²+8x+15

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

CCSS.HSA.SSE.B.3

Find the quadratic function of the graph that passes through the given points,
(-3,0), (-2,8), & (1,0) in intercept form.

•  $y=-\frac{8}{11}\left(x+3\right)\left(x-1\right)$ 

•  $y=\left(x+3\right)\left(x-1\right)$ 

•  $y=x^2+2x-3$ 

•  $y=-\frac{8}{3}\left(x+3\right)\left(x-1\right)$ 

Given the roots and a point on the quadratic, find the intercept form for each quadratic.

Roots are 3, -4 and the y-int is 6.

• $f\left(x\right)=-\frac{1}{2}\left(x-3\right)\left(x+4\right)$

• $f\left(x\right)=\frac{1}{2}\left(x-3\right)\left(x+4\right)$

• $f\left(x\right)=\left(x-3\right)\left(x+4\right)$

• $f\left(x\right)=\left(x+3\right)\left(x-4\right)$

Given the roots and a point on the quadratic, find the intercept form for each quadratic.
Roots are  $2\pm\sqrt{3}$  and y-int is 3 

•  $y=\left(x-2+\sqrt{3}\right)\left(x-2-\sqrt{3}\right)$  

•  $y=3\left(x-2+\sqrt{3}\right)\left(x-2-\sqrt{3}\right)$  

•  $y=3\left(x+2+\sqrt{3}\right)\left(x+2-\sqrt{3}\right)$  

•  $y=\left(x+2+\sqrt{3}\right)\left(x+2-\sqrt{3}\right)$  

Given the roots and a point on the quadratic, find the intercept form for each quadratic.
Roots are  $\pm i$  and passes through (0,3)

•  $f\left(x\right)=3\left(x-1\right)\left(x+1\right)$  

•  $f\left(x\right)=\frac{1}{3}\left(x-i\right)\left(x+i\right)$  

•  $f\left(x\right)=\left(x-i\right)\left(x+i\right)$  

•  $f\left(x\right)=3\left(x-i\right)\left(x+i\right)$