Solving Quadratics

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.4

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

Solve by factoring:

4x²+16x+15=0

• {-5/2 , -3/2}

• (2x+5)(2x+3)

• {-10 , -6}

• {5/2 , 3/2}

Solve
(4a + 3)(4a - 3) = 0

• a = ^-3/₄, ³/₄ 
• a = ^-4/₃, ⁴/₃ 
• a = ^-9/₁₆, ⁹/₁₆ 
• a = ^-16/₉, ¹⁶/₉ 

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.2

What are the solutions?

• {-2 , 1}

• {1 , 2}

• {-1 , 2}

• {0 , -4}

 $3x\left(2x-4\right)=0$  

Solve the equation using the zero product property. 

• x = -1/3 or x = -2

• x = 0 or x = 2

• x = 0 or x = -2

• x = -1/3 or x = 2

Find the zeros of the equation: 
(x+10)(x-2) = 0

• 10 and 2
• -2 and 10
• -10 and 2
• -2 and -10

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

How many solutions does the equation 4x² + 4x + 1 = 0 have?

• 0
• 1
• 2
• More than 2

Tags

CCSS.HSA-REI.B.4B

If the graph of a quadratic does not intercept the x axis at any point, then it has:

• 1 Real Solution
• 2 Real Solutions
• Half a Solution
• No Real Solution

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.REI.B.4

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Tags

CCSS.HSA-REI.B.4B