Math 1 Unit 4 Lesson 13

Solve for the values of x:

(x - 5)(x - 1) = 0

• (5, 0) or (1, 0)

• (-5, 0) or (-1, 0)

• (0, -5) or (0, -1)

• (0, 5) or (0, 1)

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

Solve for b

• b=4/5, b=3

• b=4, b=-3

• b=1/5, b=3

• b=4/5, b=-3

Tags

CCSS.HSA-REI.B.4B

What are the solutions?

(2x + 5)(5x - 2) = 0

• x = -5/2, -2/5

• x = -5/2, 2/5

• x = 5/2, 2/5

• x = 5/2, -2/5

Tags

CCSS.HSA-REI.B.4B

What are the x-intercepts?

2(x + 5)(x + 1) = 0

• x = 0, 5, 1

• x = 0, - 5, -1

• x = 5, 1

• x = -5, -1

Tags

CCSS.HSA-REI.B.4B

What are the zeros?

2x(x - 5) = 0

• x = 0, 5

• x = 0, - 5

• x = 5

• x = -5

Tags

CCSS.HSF-IF.C.7C

• -2 and 10

• -2 and -10

• 2 and 10

• 2 and -10

Tags

CCSS.HSA-REI.B.4B

Find the zero(s) of the function.

• x = 1
• x = -3
• x = {-1, 3}
• x = 2

Tags

CCSS.HSF-IF.C.7A