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GHS Algebra I - Topic 6 Lesson 3 Exponential Growth/Decay

Authored by Thomas Morrison

Mathematics

8th - 12th Grade

CCSS covered

Used 36+ times

GHS Algebra I - Topic 6 Lesson 3 Exponential Growth/Decay
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18 questions

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1.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

What kinds of situations can be modeled with exponential growth or exponential decay functions? Check all that apply.

Loan interest, appreciation and depreciation of assets and investments

Growth or decline of populations of living things

Spread of organic and computer viruses, pandemics, epidemics

Radioactive half-life calculations

Distance as a function of rate times time

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the basic form of an exponential function?

y=mx+by=mx+b

f(x)=a(xh)2+kf\left(x\right)=a\left(x-h\right)^2+k

E=mc2E=mc^2

f(x)=abxf\left(x\right)=a\cdot b^x

yy1=m(xx1)y-y_1=m\left(x-x_1\right)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the basic form of an exponential growth function?

y=mx+by=mx+b

f(x)=a(xh)2+kf\left(x\right)=a\left(x-h\right)^2+k

 End Value=Initial Value(1Decay Rate)TimeEnd\ Value=Initial\ Value\cdot\left(1-Decay\ Rate\right)^{Time} 

 End Value=Initial Value (1+Growth Rate)TimeEnd\ Value=Initial\ Value\ \cdot\left(1+Growth\ Rate\right)^{Time} 

 A=P(1+rn)n  tA=P\left(1+\frac{r}{n}\right)^{n\ \cdot\ t} 

Tags

CCSS.HSF-IF.C.8B

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the basic form of an exponential decay function?

y=mx+by=mx+b

f(x)=a(xh)2+kf\left(x\right)=a\left(x-h\right)^2+k

 End Value=Initial Value(1Decay Rate)TimeEnd\ Value=Initial\ Value\cdot\left(1-Decay\ Rate\right)^{Time} 

 End Value=Initial Value (1+Growth Rate)TimeEnd\ Value=Initial\ Value\ \cdot\left(1+Growth\ Rate\right)^{Time} 

 A=P(1+rn)n  tA=P\left(1+\frac{r}{n}\right)^{n\ \cdot\ t} 

Tags

CCSS.HSF-IF.C.8B

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the basic form of a compound interest function?

y=mx+by=mx+b

f(x)=a(xh)2+kf\left(x\right)=a\left(x-h\right)^2+k

 End Value=Initial Value(1Decay Rate)TimeEnd\ Value=Initial\ Value\cdot\left(1-Decay\ Rate\right)^{Time} 

 End Value=Initial Value (1+Growth Rate)TimeEnd\ Value=Initial\ Value\ \cdot\left(1+Growth\ Rate\right)^{Time} 

 A=P(1+rn)n  tA=P\left(1+\frac{r}{n}\right)^{n\ \cdot\ t} 

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

The population of Hillville is 5,000 people. It grows at an annual rate of 15%. What will the estimated population of Hillville be in five years?

5,750 people

3,750 people

8,750 people

5,380 people

10,057 people

Tags

CCSS.HSF-LE.A.1C

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kim’s family invested in a Certificate of Deposit (CD) for her when she was born. The initial value is $3,000, the annual interest rate is 8%, and the interest is compounded quarterly. What is the value of the CD at the end of five years?

$3,000.98

$4,200.00

$3,240.00

$4,407.98

$4,457.84

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