Factoring Quadratics to Find Solutions

Solve the following quadratic equation that has already been factored.

(x - 3)(x + 6) = 0

• x = 3 and x = 6

• x = 3 and x = -6

• x = -3 and x = 6

• x = -3 and x = -6

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratic equation that has already been factored.

(x + 5)(x + 7) = 0

• x = 5 and x = 7

• x = 5 and x = -7

• x = -5 and x = 7

• x = -5 and x = -7

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratic equation that has already been factored.

(2x + 5)(x - 8) = 0

• x = 5/2 and x = 8

• x = 5/2 and x = -8

• x = -5/2 and x = 8

• x = -5/2 and x = -8

Tags

CCSS.HSA-REI.B.4B

Factor the following quadratic

 $x^2\ +\ 4x\ +\ 3\ =\ 0$  

• (x+4)(x+1)=0

• (x+3)(x+1)=0

• (x+4)(x-1)=0

• (x-3)(x-1)=0

Tags

CCSS.HSA-REI.B.4B

Now that you previously factored the quadratic, finish the problem by solving for the solutions.

 $x^2\ +\ 4x\ +\ 3\ =\ 0$  

• x = -1 and x = -3

• x = 1 and x = 3

• x = -1 and x = 3

• x = 1 and x = -3

Tags

CCSS.HSA-REI.B.4B

Factor the following quadratic

 $x^2\ -\ 3x\ -\ 28\ =\ 0$ 

• (x-7)(x+4)=0

• (x+7)(x-4)=0

• (x+14)(x-2)=0

• (x-14)(x+2)=0

Tags

CCSS.HSA-REI.B.4B

Now that you previously factored the quadratic, finish the problem by solving for the solutions.

 $x^2\ -\ 3x\ -\ 28\ =\ 0$ 

• x = -7 and x = -4

• x = 7 and x = 7

• x = 7 and x = -4

• x = -7 and x = 4

Tags

CCSS.HSA-REI.B.4B

Factor the following quadratic

 $x^2\ -\ 14x\ +\ 40\ =\ 0$ 

• (x-5)(x-8)=0

• (x+5)(x+8)=0

• (x+10)(x+4)=0

• (x-10)(x-4)=0

Tags

CCSS.HSA-REI.B.4B

Now that you previously factored the quadratic, finish the problem by solving for the solutions.

 $x^2\ -\ 14x\ +\ 40\ =\ 0$ 

• x = -10 and x = -4

• x = 10 and x = 4

• x = 10 and x = -4

• x = -10 and x = 4

Tags

CCSS.HSA-REI.B.4B

Factor then solve the following quadratic equation.

 $x^2\ +\ 2x\ -24\ =\ 0$ 

• x = -6 and x = -4

• x = 6 and x = 4

• x = 6 and x = -4

• x = -6 and x = 4

Tags

CCSS.HSA-REI.B.4B