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CHAIN RULE

Authored by JV Generalao

Mathematics

11th - 12th Grade

10 Questions

CCSS covered

Used 22+ times

CHAIN RULE
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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is the inner part of the composite function

 y=(sin x)2y=\left(\sin\ x\right)^2  

 x2x^2  

 sinx2\sin x^2  

 sinx\sin x  

this is not a composite function

Tags

CCSS.HSF-BF.A.1C

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is the derivative of the function  f(x)=cos (5x4)?f\left(x\right)=\cos\ \left(5x^4\right)?  

 f(x)=sin(20x3)f'\left(x\right)=\sin\left(20x^3\right)  

 f(x)=sin(20x3)f'\left(x\right)=-\sin\left(20x^3\right)  

 f(x)=20x3sin(5x4)f'\left(x\right)=20x^3\sin\left(5x^4\right)  

 f(x)=20x3sin(5x4)f'\left(x\right)=-20x^3\sin\left(5x^4\right)  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find y' if  y=\tan\left(3x^2+2\right)  

 y=6xsec2(3x2+2)y'=6x\sec^2\left(3x^2+2\right)  

 y=sec2(3x2+2)y'=\sec^2\left(3x^2+2\right)  

 y=sec2(6x)y'=\sec^2\left(6x\right)  

 y=6xsec2x(3x2+2)y'=6x\sec^2x\left(3x^2+2\right)  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find y' if
 y=sin(2x2)y=\sin\left(2x^2\right)  .

 y=4sin(2x2)y'=4\sin\left(2x^2\right)  

 y=4xcos(2x2)y'=4x\cos\left(2x^2\right)  

 y=2xcos(2x2)y'=2x\cos\left(2x^2\right)  

 y=xcos(4x2)y'=x\cos\left(4x^2\right)  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of  y=(2x+1)10y=\left(2x+1\right)^{10}  

 y=10(2x+1)9y'=10\left(2x+1\right)^9  

 y=20(2x+1)10y'=20\left(2x+1\right)^{10}  

 y=20(2x1)9y'=20\left(2x-1\right)^9  

 y=20(2x+1)9y'=20\left(2x+1\right)^9  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of
 f(x)=(x32x)2f\left(x\right)=\left(x^3-2x\right)^2  

 f(x)=6x516x3+8xf'\left(x\right)=6x^5-16x^3+8x  

 f(x)=6x512x3+8xf'\left(x\right)=6x^5-12x^3+8x  

 f(x)=x64x4+4x2f'\left(x\right)=x^6-4x^4+4x^2  

 f(x)=6x516x38xf'\left(x\right)=6x^5-16x^3-8x  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of  f\left(x\right)=\left(x^6+4\right)^5\  .

 f(x)=5x5(x4+4)4f'\left(x\right)=5x^5\left(x^4+4\right)^4  

 f(x)=30x5(x6+4)4f'\left(x\right)=30x^5\left(x^6+4\right)^4  

 f(x)=6x5(x6+4)4f'\left(x\right)=6x^5\left(x^6+4\right)^4  

 f(x)=30x6(x6+4)4f'\left(x\right)=30x^6\left(x^6+4\right)^4  

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