Search Header Logo

cpcalc 3.3.3

Authored by Brian Reed

Mathematics

12th Grade

Used 1+ times

cpcalc 3.3.3
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Differentiate:
f(x) = x7 (5 + 8x)3

f '(x) = x2 (5 + 8x)6 (35 + 80x)
f '(x) = x6 (5 + 8x)2 (35 + 80x)
f '(x) = 8x7 (5 + 8x)2 (35 + 80x)
f '(x) = x6 (5 + 8x)3 (35 + 80x)

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Find  dydx if y=x3x1\frac{dy}{dx}\ if\ y=\frac{x^3}{x-1}  

 2x33x2(x1)2\frac{2x^3-3x^2}{\left(x-1\right)^2}  

 2x3+3x2(x1)2\frac{2x^3+3x^2}{\left(x-1\right)^2}  

 2x33x2(x1)2\frac{-2x^3-3x^2}{\left(x-1\right)^2}  

 2x3+3x2(x1)2\frac{-2x^3+3x^2}{\left(x-1\right)^2}  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Differentiate (2x + 2)(x - 5)8 with respect to x.

(2x + 2)(x - 5)7 + 2(x - 5)8
8(2x + 2)(x - 5)7 + 2(x - 5)8
2(x - 5)8
16(x - 5)7

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

.

Only the Quotient Rule
The Quotient and Product Rules
The Quotient and Chain Rules
Only the Chain Rule

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Find the slope of the line tangent to the graph of y=2x+1y=\sqrt{2x+1}  at the point  (4, 3)\left(4,\ 3\right)  

 13\frac{1}{3}  

 23\frac{2}{3}  

 43\frac{4}{3}  

 16\frac{1}{6}  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Find yy' if  y=10(x2x+1)5y=10\left(\frac{x}{2x+1}\right)^5   

 y=50x4(2x+1)6y'=\frac{50x^4}{\left(2x+1\right)^6}  

 y=50x4(2x+1)3y'=\frac{50x^4}{\left(2x+1\right)^3}  

 y=50x4(2x+1)5y'=\frac{50x^4}{\left(2x+1\right)^5}  

 y=50x4(2x+1)4y'=\frac{-50x^4}{\left(2x+1\right)^4}  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?