Trig Ratios & Finding Missing Sides

Trig Ratios & Finding Missing Sides

8th - 11th Grade

25 Qs

quiz-placeholder

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Trig Ratios & Finding Missing Sides

Trig Ratios & Finding Missing Sides

Assessment

Quiz

Mathematics

8th - 11th Grade

Hard

CCSS
HSG.SRT.C.8, HSG.SRT.C.6, HSG.SRT.C.7

+4

Standards-aligned

Created by

Brittany French

Used 40+ times

FREE Resource

25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the memory trick for trig ratios?

SOH CAH TOA

SAH COH TOA

SOH CAH TOH

SO CA TOA

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

sin(67°)=16x\sin\left(67\degree\right)=\frac{16}{x}

sin(67°)=x16\sin\left(67\degree\right)=\frac{x}{16}

tan(67°)=16x\tan\left(67\degree\right)=\frac{16}{x}

cos(67°)=x16\cos\left(67\degree\right)=\frac{x}{16}

cos(67°)=16x\cos\left(67\degree\right)=\frac{16}{x}

Tags

CCSS.HSF.TF.A.3

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

cos(17°)=x14\cos\left(17\degree\right)=\frac{x}{14}

cos(17°)=14x\cos\left(17\degree\right)=\frac{14}{x}

sin(17°)=x14\sin\left(17\degree\right)=\frac{x}{14}

sin(17°)=14x\sin\left(17\degree\right)=\frac{14}{x}

tan(17°)=x14\tan\left(17\degree\right)=\frac{x}{14}

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

tan(22°)=18x\tan\left(22\degree\right)=\frac{18}{x}

tan(22°)=x18\tan\left(22\degree\right)=\frac{x}{18}

sin(22°)=18x\sin\left(22\degree\right)=\frac{18}{x}

sin(22°)=x18\sin\left(22\degree\right)=\frac{x}{18}

cos(22°)=x18\cos\left(22\degree\right)=\frac{x}{18}

Tags

CCSS.HSF.TF.A.3

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

tan(26°)=18x\tan\left(26\degree\right)=\frac{18}{x}

tan(26°)=x18\tan\left(26\degree\right)=\frac{x}{18}

sin(26°)=18x\sin\left(26\degree\right)=\frac{18}{x}

sin(26°)=x18\sin\left(26\degree\right)=\frac{x}{18}

cos(26°)=x18\cos\left(26\degree\right)=\frac{x}{18}

Tags

CCSS.HSF.TF.A.3

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

sin(57°)=16x\sin\left(57\degree\right)=\frac{16}{x}

sin(57°)=x16\sin\left(57\degree\right)=\frac{x}{16}

cos(57°)=x16\cos\left(57\degree\right)=\frac{x}{16}

tan(57°)=16x\tan\left(57\degree\right)=\frac{16}{x}

cos(57°)=x16\cos\left(57\degree\right)=\frac{x}{16}

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

What is the correct equation for this diagram?

cos(57°)=x11\cos\left(57\degree\right)=\frac{x}{11}

cos(57°)=11x\cos\left(57\degree\right)=\frac{11}{x}

tan(57°)=x11\tan\left(57\degree\right)=\frac{x}{11}

tan(57°)=11x\tan\left(57\degree\right)=\frac{11}{x}

sin(57°)=x11\sin\left(57\degree\right)=\frac{x}{11}

Tags

CCSS.HSF.TF.A.3

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

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