Zero Product Property , Factoring Quadratics

Use the Zero Product Property to solve for the values of x.

 $\left(x+2\right)\left(x-3\right)=0$  

• 2 and 3

• -2 and -3

• 2 and -3

• -2 and 3

Tags

CCSS.HSA-REI.B.4B

Solve using the Zero Product Property:
 $\left(3x+2\right)\left(x+1\right)=0$  

•  $x=1,\ x=\frac{2}{3}$  

•  $x=-1,\ \ x=-\frac{2}{3}$  

•  $x=2,\ x=1$  

•  $x=-1,\ \ x=\frac{2}{3}$  

Tags

CCSS.HSA-REI.B.4B

What are the zeros of the function?

  $0=(2x+5)(x-6)$  

•  $x=-6,\ x=\frac{5}{2}$  

•  $x\ =-\frac{5}{2},\ x=6$  

•  $x=-5,\ x\ =\ 6$  

•  $x=5,\ x\ =-6$  

Tags

CCSS.HSF-IF.C.7C

Solve.  

 $r\left(r+7\right)=0$  

•  $r=0,\ r=-7$  

•  $r=0,\ r=7$  

•  $r=-7$  

•  $r=7$  

Tags

CCSS.HSA-REI.B.4B

Factor and Solve: Remember the two numbers you choose when factoring, are not your solutions to the equation!

a² + 2a − 24 = 0

• a = −6, 4

• a = 6, −4

• a = 12, −2

• a = 8, −3

Tags

CCSS.HSA-REI.B.4B

Factor and Solve: Remember the two numbers you choose when factoring, are not your solutions to the equation!

x² + 13x + 12 = 0

• x = −12, −1

• x = 12, 1

• x = 13, 1

• x = −13, −1

Tags

CCSS.HSA-REI.B.4B