Solving quadratics practice

What are the roots?
(x + 5)(2x - 3) = 0

• x = 5 ; x =  -³/₂
• x = -5 ; x = ³/₂
• x = -5 ; x = 3
• 2x² + 7x - 15

What are the roots?
2x² + 2x - 12 = 0

• x = 3 ; x = -3
• x = 12 ; x =  -12
• x = -3 ; x = 2
• x = -2 ; x = 2

What are the zeros of the function?
f(x) = x² + x - 20

• x = 5 ; x = -4
• x = -20 ; x = 0
• x = -5 ; x = 4
• x = 20; x = 0

Next step in completing the square?
3x² + 18x - 6 = 0
1: 3x² + 18x  = 6
2: 3(x² + 6x) = 6
3: ?

• 3(x² + 6x + 9) = 6 + 9
• 3(x² + 6x + 36) = 6 + 36
• (x² + 6x) = 9
• 3(x² + 6x + 9) = 6 + 27

Which quadratic is being solved in the formula?

• 2x² - 5x + 3
• 2x² + 5x + 3
• 3x² - 5x + 2
• 2x² - 5x - 3

Solve:
x² - 49 = 0

• x = -7, x = 7
• x = -7
• x = 7
• x = -7, x = 1

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Solve by the Quadratic Formula:

 $9u^2-11u+7=0$  

•  $\frac{-11\pm\sqrt{131}}{18}$  

•  $\frac{11\pm\sqrt{131}}{18}$  

•  $\frac{11\pm\sqrt{131}}{-18}$  

•  $\frac{11\pm i\sqrt{373}}{18}$  

Solve by factoring.

• -4, 2

• -2, 4

• -16

• -4

Solve the following quadratics equation by completing the square...

x² + 12x + 10 = 0

• x = -6 ± √26

• x = 6 ± √26

• x = 26 ± √6

• x = -26 ± √6