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Day 57 Unit 6 Review for Test

Authored by T. Meaney

Mathematics

9th Grade

Used 5+ times

Day 57 Unit 6 Review for Test
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7 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

How does the graph of

 g(x)=x2g\left(x\right)=x^2  compare to the graph of  f(x)=(x+4)2+2f\left(x\right)=\left(x+4\right)^2+2  

 f(x)f\left(x\right)  is shifted left 4 and down 2

 f\left(x\right)  is shifted right 4 and up 2

 f\left(x\right)  is shifted left 4 and up 2

 f\left(x\right)  is shifted right 4 and down 2

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which transformation of  y=f(x)y=f\left(x\right)  moves the graph 7 units left and 3 units down?

 y=f(x+7)3y=f\left(x+7\right)-3  

 y=f(x+7)+3y=f\left(x+7\right)+3  

 y=f(x7)3y=f\left(x-7\right)-3  

 y=f(x7)+3y=f\left(x-7\right)+3  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Factor  x26x16x^2-6x-16  

 (x+2)(x+8)\left(x+2\right)\left(x+8\right)  

 (x2)(x+8)\left(x-2\right)\left(x+8\right)  

 (x+2)(x8)\left(x+2\right)\left(x-8\right)  

 (x2)(x8)\left(x-2\right)\left(x-8\right)  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

A quadratic function that opens down with vertex (-1,4) is represented in the graph provided. If the domain is all real numbers, describe the range of the function.

y4y\le4

y4y\ge4

y1y\le-1

y1y\ge-1

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Does the quadratic function  y=x26x+5y=x^2-6x+5    have a maximum of minimum? Why?

The function has a maximum because a<0.

The function has a maximum because a>0.

The function has a minimum because a<0.

The function has a minimum because a>0.

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Which equation is equivalent to  y=x26x+5y=x^2-6x+5  ?

 y=(x+3)24y=\left(x+3\right)^2-4  

 y=(x3)24y=\left(x-3\right)^2-4  

 y=(x3)2+4y=\left(x-3\right)^2+4  

 y=(x3)2+5y=\left(x-3\right)^2+5  

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

If  f\left(x\right)=x^2+4x-1   and  g\left(x\right)=x-3   , find the value(s) of  x   that satisfy  f\left(x\right)=g\left(x\right)  .

 {2,1}\left\{-2,1\right\}  

 (2,5) and (1,4)\left(-2,-5\right)\ and\ \left(-1,-4\right)  

 (2,5)\left(-2,-5\right)  

 {2}\left\{-2\right\}  

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