Тригонометрические формулы. Часть 1

Тригонометрические формулы. Часть 1

10th Grade

19 Qs

quiz-placeholder

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Тригонометрические формулы. Часть 1

Тригонометрические формулы. Часть 1

Assessment

Quiz

Mathematics

10th Grade

Practice Problem

Medium

Created by

Ольга Харченко

Used 29+ times

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19 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

основное тригонометрическое тождество

 sin2α+cos2α=1\sin^2\alpha+\cos^2\alpha=1  

 1+tg2α=1cos2α1+tg^2\alpha=\frac{1}{\cos^2\alpha}  

 1+ctg2α=1sin2α1+\operatorname{ctg}^2\alpha=\frac{1}{\sin^2\alpha}  

 tgαctgα=1tg\alpha\operatorname{ctg}\alpha=1  

2.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

продолжите формулу  1+tg2α=1+tg^2\alpha=  

 sin2α+cos2α\sin^2\alpha+\cos^2\alpha  

 1cos2α\frac{1}{\cos^2\alpha}  

 1sin2α\frac{1}{\sin^2\alpha}  

 tgαctgαtg\alpha\operatorname{ctg}\alpha  

3.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

продолжите формулу  1+ctg2α=1+\operatorname{ctg}^2\alpha=  

 sin2α+cos2α\sin^2\alpha+\cos^2\alpha  

 1cos2α\frac{1}{\cos^2\alpha}  

 1sin2α\frac{1}{\sin^2\alpha}  

 tgαctgαtg\alpha\operatorname{ctg}\alpha  

4.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

продолжите формулу  tgαctgα=tg\alpha\operatorname{ctg}\alpha=  

 sin2α+cos2α\sin^2\alpha+\cos^2\alpha  

 1cos2α\frac{1}{\cos^2\alpha}  

 1sin2α\frac{1}{\sin^2\alpha}  

1

5.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

 cos (αβ)=\cos\ \left(\alpha-\beta\right)=  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

 sinαcos+cosαsinβ\sin\alpha\cos+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

6.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

 cos (α+β)=\cos\ \left(\alpha+\beta\right)=  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

 sinαcos+cosαsinβ\sin\alpha\cos+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

7.

MULTIPLE CHOICE QUESTION

0 sec • 1 pt

 sin (α+β)=\sin\ \left(\alpha+\beta\right)=  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

 sinαcos+cosαsinβ\sin\alpha\cos+\cos\alpha\sin\beta  

 sinαcosβcosαsinβ\sin\alpha\cos\beta-\cos\alpha\sin\beta  

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