ctg ⁡ α 2 = ? \operatorname{ctg}\ \frac{\alpha}{2}=? c t g 2 α = ?

1 + cos ⁡ α sin ⁡ α \frac{1+\cos\alpha}{\sin\alpha} sin α 1 + cos α

sin ⁡ α 1 − cos ⁡ α \frac{\sin\alpha}{1-\cos\alpha} 1 − cos α sin α

sin ⁡ α 1 + cos ⁡ α \frac{\sin\alpha}{1+\cos\alpha} 1 + cos α sin α

1 − cos ⁡ α sin ⁡ α \frac{1-\cos\alpha}{\sin\alpha} sin α 1 − cos α

t g α 2 = ? tg\ \frac{\alpha}{2}=? t g 2 α = ?

sin ⁡ α 1 + cos ⁡ α \frac{\sin\alpha}{1+\cos\alpha} 1 + cos α sin α

1 − cos ⁡ α sin ⁡ α \frac{1-\cos\alpha}{\sin\alpha} sin α 1 − cos α

1 + cos ⁡ α sin ⁡ α \frac{1+\cos\alpha}{\sin\alpha} sin α 1 + cos α

sin ⁡ α 1 − cos ⁡ α \frac{\sin\alpha}{1-\cos\alpha} 1 − cos α sin α

sin ⁡ α + sin ⁡ β = ? \sin\alpha+\sin\beta=? sin α + sin β = ?

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

sin ⁡ α − sin ⁡ β = ? \sin\alpha-\sin\beta=? sin α − sin β = ?

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

cos ⁡ α − cos ⁡ β = ? \cos\alpha-\cos\beta=? cos α − cos β = ?

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

cos ⁡ α + cos ⁡ β = ? \cos\alpha+\cos\beta=? cos α + cos β = ?

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

Көбейтіндіні қосындыға түрлендірудің дұрыс формулаларын белгілеңіз

cos ⁡ α ⋅ cos ⁡ β = 1 2 [ cos ⁡ ( α + β ) + cos ⁡ ( α − β ) ] \cos\alpha\cdot\cos\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)+\cos\left(\alpha-\beta\right)\right] cos α ⋅ cos β = 2 1 [ cos ( α + β ) + cos ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α − β ) − cos ⁡ ( α + β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha-\beta\right)-\cos\left(\alpha+\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α − β ) − cos ( α + β ) ]

sin ⁡ α ⋅ cos ⁡ β = 1 2 [ sin ⁡ ( α + β ) + sin ⁡ ( α − β ) ] \sin\alpha\cdot\cos\beta=\frac{1}{2}\left[\sin\left(\alpha+\beta\right)+\sin\left(\alpha-\beta\right)\right] sin α ⋅ cos β = 2 1 [ sin ( α + β ) + sin ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α + β ) + cos ⁡ ( α − β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)+\cos\left(\alpha-\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α + β ) + cos ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α + β ) − cos ⁡ ( α − β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)-\cos\left(\alpha-\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α + β ) − cos ( α − β ) ]

Тригонометрия формулалары1

Authored by Gulnur Ertaeva

Mathematics

9th Grade

Used 19+ times

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

12 questions

Show all answers

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Қос бұрыштың дұрыс формулаларын белгілеңіз

$\cos2a=\sin^2\alpha-\cos^2\alpha$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

$tg2\alpha=\frac{2tg\alpha}{1-tg^2\alpha}$

$tg2\alpha=\frac{2tg\alpha}{1+tg^2\alpha}$

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Қос бұрыштың дұрыс формулаларын белгілеңіз

$\cos2a=\cos^2\alpha-\sin^2\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\beta$

$\operatorname{ctg}2\alpha=\frac{1}{2\left(\operatorname{ctg}\alpha-tg\alpha\right)}$

$tg2\alpha=\frac{2tg\alpha}{1-tg^2\alpha}$

$\operatorname{ctg}2\alpha=\frac{1}{2}\left(\operatorname{ctg}\alpha-tg\alpha\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{1-\cos\alpha}{2}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{1+\cos\alpha}{2}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{\sin\alpha}{1+\cos\alpha}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

дұрыс жауап жоқ

MULTIPLE SELECT QUESTION

45 sec • 1 pt

$\operatorname{ctg}\ \frac{\alpha}{2}=?$

$\frac{1+\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1+\cos\alpha}$

$\frac{1-\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1-\cos\alpha}$

MULTIPLE SELECT QUESTION

45 sec • 1 pt

$tg\ \frac{\alpha}{2}=?$

$\frac{1+\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1+\cos\alpha}$

$\frac{1-\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1-\cos\alpha}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\alpha+\sin\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\alpha-\sin\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\alpha-\cos\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Microsoft

or continue with

Facebook

Apple

Others

Already have an account?

Similar Resources on Wayground

14 questions

Matematik PT3 Trigonometri

Quiz

•

8th - 9th Grade

11 questions

Trig Formulas (Sum/Difference & Double Angle)

Quiz

•

9th - 12th Grade

11 questions

solving for missing sides using trig

Quiz

•

9th - 10th Grade

10 questions

Precalc A LT #6

Quiz

•

9th - 12th Grade

10 questions

Números Reales

Quiz

•

9th Grade

17 questions

SohCahToa (1)

Quiz

•

9th - 10th Grade

15 questions

More Trig

Quiz

•

9th - 11th Grade

15 questions

Conocimientos Previos

Quiz

•

5th - 10th Grade

Popular Resources on Wayground

24 questions

PBIS-HGMS Day 10

Quiz

•

6th - 8th Grade

10 questions

HCS SCI 03 Summer School Review 3

Quiz

•

3rd Grade

11 questions

Home Scope

Quiz

•

7th - 8th Grade

15 questions

HCS SCI 05 Summer School Assessment 3 Review

Quiz

•

5th Grade

35 questions

Lufkin Road Middle School Student Handbook & Policies Assessment

Quiz

•

7th Grade

18 questions

Geo 11.3 Area of Circles and Sectors

Quiz

•

9th - 11th Grade

Discover more resources for Mathematics

18 questions

Geo 11.3 Area of Circles and Sectors

Quiz

•

9th - 11th Grade

Тригонометрия формулалары1

Қос бұрыштың дұрыс формулаларын белгілеңіз

Қос бұрыштың дұрыс формулаларын белгілеңіз

1−cos⁡α2=?\frac{1-\cos\alpha}{2}=?21−cosα​=?

1+cos⁡α2=?\frac{1+\cos\alpha}{2}=?21+cosα​=?

sin⁡α1+cos⁡α=?\frac{\sin\alpha}{1+\cos\alpha}=?1+cosαsinα​=?

ctg⁡ α2=?\operatorname{ctg}\ \frac{\alpha}{2}=?ctg 2α​=?

tg α2=?tg\ \frac{\alpha}{2}=?tg 2α​=?

sin⁡α+sin⁡β=?\sin\alpha+\sin\beta=?sinα+sinβ=?

sin⁡α−sin⁡β=?\sin\alpha-\sin\beta=?sinα−sinβ=?

cos⁡α−cos⁡β=?\cos\alpha-\cos\beta=?cosα−cosβ=?

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

$\frac{1-\cos\alpha}{2}=?$

$\frac{1+\cos\alpha}{2}=?$

$\frac{\sin\alpha}{1+\cos\alpha}=?$

$\operatorname{ctg}\ \frac{\alpha}{2}=?$

$tg\ \frac{\alpha}{2}=?$

$\sin\alpha+\sin\beta=?$

$\sin\alpha-\sin\beta=?$

$\cos\alpha-\cos\beta=?$