ctg ⁡ α 2 = ? \operatorname{ctg}\ \frac{\alpha}{2}=? c t g 2 α = ?

1 + cos ⁡ α sin ⁡ α \frac{1+\cos\alpha}{\sin\alpha} sin α 1 + cos α

sin ⁡ α 1 − cos ⁡ α \frac{\sin\alpha}{1-\cos\alpha} 1 − cos α sin α

sin ⁡ α 1 + cos ⁡ α \frac{\sin\alpha}{1+\cos\alpha} 1 + cos α sin α

1 − cos ⁡ α sin ⁡ α \frac{1-\cos\alpha}{\sin\alpha} sin α 1 − cos α

t g α 2 = ? tg\ \frac{\alpha}{2}=? t g 2 α = ?

sin ⁡ α 1 + cos ⁡ α \frac{\sin\alpha}{1+\cos\alpha} 1 + cos α sin α

1 − cos ⁡ α sin ⁡ α \frac{1-\cos\alpha}{\sin\alpha} sin α 1 − cos α

1 + cos ⁡ α sin ⁡ α \frac{1+\cos\alpha}{\sin\alpha} sin α 1 + cos α

sin ⁡ α 1 − cos ⁡ α \frac{\sin\alpha}{1-\cos\alpha} 1 − cos α sin α

sin ⁡ α + sin ⁡ β = ? \sin\alpha+\sin\beta=? sin α + sin β = ?

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

sin ⁡ α − sin ⁡ β = ? \sin\alpha-\sin\beta=? sin α − sin β = ?

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

cos ⁡ α − cos ⁡ β = ? \cos\alpha-\cos\beta=? cos α − cos β = ?

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

cos ⁡ α + cos ⁡ β = ? \cos\alpha+\cos\beta=? cos α + cos β = ?

2 cos ⁡ α + β 2 cos ⁡ α − β 2 2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 cos 2 α + β cos 2 α − β

2 sin ⁡ α + β 2 cos ⁡ α − β 2 2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2} 2 sin 2 α + β cos 2 α − β

2 sin ⁡ α − β 2 cos ⁡ α + β 2 2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\ 2 sin 2 α − β cos 2 α + β

− 2 sin ⁡ α + β 2 sin ⁡ α − β 2 -2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2} − 2 sin 2 α + β sin 2 α − β

Көбейтіндіні қосындыға түрлендірудің дұрыс формулаларын белгілеңіз

cos ⁡ α ⋅ cos ⁡ β = 1 2 [ cos ⁡ ( α + β ) + cos ⁡ ( α − β ) ] \cos\alpha\cdot\cos\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)+\cos\left(\alpha-\beta\right)\right] cos α ⋅ cos β = 2 1 [ cos ( α + β ) + cos ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α − β ) − cos ⁡ ( α + β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha-\beta\right)-\cos\left(\alpha+\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α − β ) − cos ( α + β ) ]

sin ⁡ α ⋅ cos ⁡ β = 1 2 [ sin ⁡ ( α + β ) + sin ⁡ ( α − β ) ] \sin\alpha\cdot\cos\beta=\frac{1}{2}\left[\sin\left(\alpha+\beta\right)+\sin\left(\alpha-\beta\right)\right] sin α ⋅ cos β = 2 1 [ sin ( α + β ) + sin ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α + β ) + cos ⁡ ( α − β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)+\cos\left(\alpha-\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α + β ) + cos ( α − β ) ]

sin ⁡ α ⋅ sin ⁡ β = 1 2 [ cos ⁡ ( α + β ) − cos ⁡ ( α − β ) ] \sin\alpha\cdot\sin\beta=\frac{1}{2}\left[\cos\left(\alpha+\beta\right)-\cos\left(\alpha-\beta\right)\right] sin α ⋅ sin β = 2 1 [ cos ( α + β ) − cos ( α − β ) ]

Тригонометрия формулалары1

Authored by Gulnur Ertaeva

Mathematics

9th Grade

Used 19+ times

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MULTIPLE SELECT QUESTION

45 sec • 1 pt

Қос бұрыштың дұрыс формулаларын белгілеңіз

$\cos2a=\sin^2\alpha-\cos^2\alpha$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

$tg2\alpha=\frac{2tg\alpha}{1-tg^2\alpha}$

$tg2\alpha=\frac{2tg\alpha}{1+tg^2\alpha}$

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Қос бұрыштың дұрыс формулаларын белгілеңіз

$\cos2a=\cos^2\alpha-\sin^2\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\beta$

$\operatorname{ctg}2\alpha=\frac{1}{2\left(\operatorname{ctg}\alpha-tg\alpha\right)}$

$tg2\alpha=\frac{2tg\alpha}{1-tg^2\alpha}$

$\operatorname{ctg}2\alpha=\frac{1}{2}\left(\operatorname{ctg}\alpha-tg\alpha\right)$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{1-\cos\alpha}{2}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{1+\cos\alpha}{2}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{\sin\alpha}{1+\cos\alpha}=?$

$\cos^2\ \frac{\alpha}{2}$

$tg^2\ \frac{\alpha}{2}$

$\sin^2\ \frac{\alpha}{2}$

$\operatorname{ctg}^2\ \frac{\alpha}{2}$

дұрыс жауап жоқ

MULTIPLE SELECT QUESTION

45 sec • 1 pt

$\operatorname{ctg}\ \frac{\alpha}{2}=?$

$\frac{1+\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1+\cos\alpha}$

$\frac{1-\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1-\cos\alpha}$

MULTIPLE SELECT QUESTION

45 sec • 1 pt

$tg\ \frac{\alpha}{2}=?$

$\frac{1+\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1+\cos\alpha}$

$\frac{1-\cos\alpha}{\sin\alpha}$

$\frac{\sin\alpha}{1-\cos\alpha}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\alpha+\sin\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\alpha-\sin\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\alpha-\cos\beta=?$

$2\sin\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\cos\frac{\alpha+\beta}{2}\cos\frac{\alpha-\beta}{2}$

$2\sin\frac{\alpha-\beta}{2}\cos\frac{\alpha+\beta}{2}\$

$-2\sin\frac{\alpha+\beta}{2}\sin\frac{\alpha-\beta}{2}$

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Тригонометрия формулалары1

Қос бұрыштың дұрыс формулаларын белгілеңіз

Қос бұрыштың дұрыс формулаларын белгілеңіз

1−cos⁡α2=?\frac{1-\cos\alpha}{2}=?21−cosα​=?

1+cos⁡α2=?\frac{1+\cos\alpha}{2}=?21+cosα​=?

sin⁡α1+cos⁡α=?\frac{\sin\alpha}{1+\cos\alpha}=?1+cosαsinα​=?

ctg⁡ α2=?\operatorname{ctg}\ \frac{\alpha}{2}=?ctg 2α​=?

tg α2=?tg\ \frac{\alpha}{2}=?tg 2α​=?

sin⁡α+sin⁡β=?\sin\alpha+\sin\beta=?sinα+sinβ=?

sin⁡α−sin⁡β=?\sin\alpha-\sin\beta=?sinα−sinβ=?

cos⁡α−cos⁡β=?\cos\alpha-\cos\beta=?cosα−cosβ=?

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$\frac{1-\cos\alpha}{2}=?$

$\frac{1+\cos\alpha}{2}=?$

$\frac{\sin\alpha}{1+\cos\alpha}=?$

$\operatorname{ctg}\ \frac{\alpha}{2}=?$

$tg\ \frac{\alpha}{2}=?$

$\sin\alpha+\sin\beta=?$

$\sin\alpha-\sin\beta=?$

$\cos\alpha-\cos\beta=?$