Тригонометриялық формулалар 2

Тригонометриялық формулалар 2

9th Grade

10 Qs

quiz-placeholder

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Тригонометриялық формулалар 2

Тригонометриялық формулалар 2

Assessment

Quiz

Mathematics

9th Grade

Hard

Created by

Gulim Ayasheva

Used 18+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

 cos(α+β)=?\cos\left(\alpha+\beta\right)=?  

 cosαcosβ+sinαsinβ\cos\alpha\cos\beta+\sin\alpha\sin\beta  

 sinαcosβ+cosαsinβ\sin\alpha\cos\beta+\cos\alpha\sin\beta  

 cosαsinβsinαcosβ\cos\alpha\sin\beta-\sin\alpha\cos\beta  

 cosαcosβsinαsinβ\cos\alpha\cos\beta-\sin\alpha\sin\beta  

2.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

 sinαcosβcosαsinβ=?\sin\alpha\cos\beta-\cos\alpha\sin\beta=?  

 sin(αβ)\sin\left(\alpha-\beta\right)  

 sin(α+β)\sin\left(\alpha+\beta\right)  

 cos(α+β)\cos\left(\alpha+\beta\right)  

 cos(αβ)\cos\left(\alpha-\beta\right)  

3.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

 tg (α+β)=?tg\ \left(\alpha+\beta\right)=?  

 sin(α+β)cosαcosβ\frac{\sin\left(\alpha+\beta\right)}{\cos\alpha\cdot\cos\beta}  

 tgα+tgβ1tgαtgβ\frac{tg\alpha+tg\beta}{1-tg\alpha\cdot tg\beta}  

 2tgα1tg2α\frac{2tg\alpha}{1-tg^2\alpha}  

 sinα1+cosα\frac{\sin\alpha}{1+\cos\alpha}  

4.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

 tg 2α=?tg\ 2\alpha=?  

 sin(α+β)cosαcosβ\frac{\sin\left(\alpha+\beta\right)}{\cos\alpha\cdot\cos\beta}  

 tgα+tgβ1tgαtgβ\frac{tg\alpha+tg\beta}{1-tg\alpha\cdot tg\beta}  

 2tgα1tg2α\frac{2tg\alpha}{1-tg^2\alpha}  

 sinα1+cosα\frac{\sin\alpha}{1+\cos\alpha}  

5.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

 2sinαcosα=?2\sin\alpha\cdot\cos\alpha=?  

 2sinα2\sin\alpha  

 2cosα2\cos\alpha  

 cos2α\cos2\alpha  

 sin2α\sin2\alpha  

6.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

 cos2α=?\cos2\alpha=?  

 cos2α+sin2α\cos^2\alpha+\sin^2\alpha  

 12sin2α1-2\sin^2\alpha  

 2sinαcosα2\sin\alpha\cdot\cos\alpha  

 2cos2α2\cos^2\alpha  

7.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

 cos2 α2=?\cos^2\ \frac{\alpha}{2}=?  

 1+cosα2\frac{1+\cos\alpha}{2}  

 1cosα2\frac{1-\cos\alpha}{2}  

 sinα1+cosα\frac{\sin\alpha}{1+\cos\alpha}  

 1cosα1+cosα\frac{1-\cos\alpha}{1+\cos\alpha}  

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