PAP 12.4 HWE Graham's Law

Compute the ratio of the effusion rate of argon to that of krypton.

• 1 Ar to 2.10 Kr

• 2.10 Ar to 1 Kr

• 1.45 Ar to 1 Kr

• 1 Ar to 1.45 Kr

An unknown gas effuses from a container in 86 seconds. The same number of moles of oxygen requires 73 seconds for an identical quantity to escape from the same starting conditions. Find the molar mass of the unknown gas.

• 19 g/mol

• 22 g/mol

• 38 g/mol

• 44 g/mol

An effusion apparatus allows a certain quantity of butane, C₄H₁₀, to escape in 136 seconds. 106 seconds are required for the same number of moles of an unknown gas to be released. What is the molar mass of the second gas?

• 35.3 g/mol

• 95.7 g/mol

• 5.9 g/mol

• 40.2 g/mol

How does the effusion rate of SO₂ compare with that of SO₃?

• 1 SO₂ : 1.12 SO₃

• 1.12 SO₂ : 1 SO₃

• 1.24 SO₂ : 1 SO₃

• 1 SO₂ : 1.24 SO₃

84 seconds and 61 seconds are the times for equal quantities of two gases to escape from an effusion apparatus under similar starting conditions. If the 84 second gas is SO₂, what is the molar mass of the other gas?

• 25.35 g/mol

• 46.53 g/mol

• 0.008 g/mol

• 33.79 g/mol