Trig DTP 4/7

Trig DTP 4/7

12th Grade

5 Qs

quiz-placeholder

Similar activities

Panjang, jisim dan isi padu cecair tahun 1

Panjang, jisim dan isi padu cecair tahun 1

1st Grade - University

10 Qs

ULANGAN BAB II MAT MINAT 12-1, 12-2

ULANGAN BAB II MAT MINAT 12-1, 12-2

12th Grade

10 Qs

THEORY ASSIGNMENT 1 DUM20132 MAY-OCT 2021 (UNIT 2 - SET 1)

THEORY ASSIGNMENT 1 DUM20132 MAY-OCT 2021 (UNIT 2 - SET 1)

12th Grade - University

10 Qs

Chapter 1 Final Practice Test

Chapter 1 Final Practice Test

11th - 12th Grade

10 Qs

FIVIZZ: WEEK 18 - ADVANCED MATHEMATICS 2

FIVIZZ: WEEK 18 - ADVANCED MATHEMATICS 2

10th Grade - University

10 Qs

ULANGAN HARIAN LIMIT FUNGSI TRIGONOMETRI

ULANGAN HARIAN LIMIT FUNGSI TRIGONOMETRI

12th Grade

10 Qs

Definite Integration

Definite Integration

12th Grade

10 Qs

Trig DTP 4/7

Trig DTP 4/7

Assessment

Quiz

Mathematics

12th Grade

Hard

Created by

Pam Fails

Used 1+ times

FREE Resource

AI

Enhance your content in a minute

Add similar questions
Adjust reading levels
Convert to real-world scenario
Translate activity
More...

5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Please select the correct solution

cos 2 x + sin 2 x=

(It's on your reference sheet!!)

1

csc 2 x + sec 2 x

sin 2 x

1 - sin 2 x

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

sin2u =

sinucosu\sin u\cos u

2sinucosu2\sin u\cos u

sin2u\sin^2u

2sin2u2\sin^2u

3.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Which of the following are equivalent to cos2u?

 cos2usin2u\cos^2u-\sin^2u  

 2cos2u12\cos^2u-1  

 12sin2u1-2\sin^2u  

 1sin2u1-\sin^2u  

 sin2ucos2u\sin^2u-\cos^2u  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

tan u/2 =

sin u1+cos u\frac{\sin\ u}{1+\cos\ u}

cos u1+sinu\frac{\cos\ u}{1+\sin u}

1+cosusinu\frac{1+\cos u}{\sin u}

sinu1cosu\frac{\sin u}{1-\cos u}

1+sinucosu\frac{1+\sin u}{\cos u}

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

tan 2u =

2tanu1tan2u\frac{2\tan u}{1-\tan^2u}

tan2u1+tanu\frac{\tan^2u}{1+\tan u}

2tanu1+tan2u\frac{2\tan u}{1+\tan^2u}

tan2u1tanu\frac{\tan^2u}{1-\tan u}