Surface Area

Area of a Parallelogram

• A = 1/2h(b1 +b2)
• A = bh
• A = 1/2bh

Tags

CCSS.6.G.A.1

What do we call this object below?

• Net 
• Triangle
• Geometry
• y = mx + b

Tags

CCSS.6.G.A.4

FInd the Surface area of the shape below?

• 258 m²
• 268 m²
• 248 m²
• 278 m²

Tags

CCSS.6.G.A.4

Find the area.

• 84 in²
• 74in²
• 150 in²
• 154 in²

Tags

CCSS.6.G.A.1

The base of the triangle is 5 inches. The length of the rectangle is 15 inches. The height of the triangle is 10 inches. Find the surface area.

• 300 inches
• 200 inches
• 275 inches

Tags

CCSS.6.G.A.4

A square pyramid is covered with decorative wrapping paper with no overlap.  The net of the box is shown on the right.  How many square centimeters of wrapping paper are needed to cover the surfaces of the box? 

• 108 cm²
• 324 cm²
• 180 cm²
• 432 cm²

Tags

CCSS.6.G.A.4

Find the surface area of the square pyramid.

• 429 sq. cm
• 389 sq. cm
• 441 sq.cm
• 377 sq. cm

Tags

CCSS.7.G.B.6

Find the surface area of the triangular pyramid. The triangle that is the base is equilateral.

• 123.6 sq. feet

• 116.8 sq. feet

• 127.9 sq. feet

• 130.9 sq. feet

Tags

CCSS.7.G.B.6

What is the surface area if you were to wrap this square pyramid?

• 23 sq. meters

• 27 sq. meters

• 33 sq. meters

• 36 sq. meters

Tags

CCSS.7.G.B.6

What is the surface area of this triangular pyramid?

• 198.9 sq. inches
• 205.6 sq. inches
• 187.9 sq. inches
• 210.6 sq. inches

Tags

CCSS.7.G.B.6