Section 1 Review

Find the midpoint of the line segment with the given endpoints (-2,-6) and (8,8)

• (-4,8)

• (18,22)

• (3,1)

• (-5,-7)

Tags

CCSS.HSG.GPE.B.6

Find the midpoint of the line segment with the given endpoints (3,9) and (5,9)

• (-1,0)

• (4,9)

• (6,7)

• (7,9)

Tags

CCSS.HSG.GPE.B.6

Find the midpoint of the segment on the graph. (Hover over picture to expand)

• (2,3)

• (-1,2)

• (5,-3)

• (3,2)

Tags

CCSS.HSG.GPE.B.6

Find the other endpoint of the line segment with the given endpoint (1,-9) and midpoint (-9,3)

• (-19,15)

• (5,-6)

• (-4,-3)

• (6,2)

Tags

CCSS.HSG.GPE.B.6

Which of the following is the correct midpoint formula given two endpoints (x₁, y₁) and (x₂, y₂)?

• 
• 
• 
• 

Tags

CCSS.HSG.GPE.B.6

How is the distance formula correctly written:

• $d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\$

• $d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)^2}$

• $d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)^2}$

• d = $\sqrt{\left(x\right)^2-\ \left(y\right)^2}$

Tags

CCSS.HSG.GPE.B.7

How is AB written in the distance formula?

• 
  $d\ =\ \sqrt{\left(5-3\right)^2\ +\ \left(0--2\right)^2}$
  

• $d\ =\ \sqrt{\left(2-5\right)^2\ +\ \left(3\ -0\right)^2}$

• $d\ =\ \sqrt{\left(5-3\right)^2\ -\ \left(0--2\right)^2}$

• $d\ =\ \sqrt{\left(4-3\right)^2\ -\ \left(2-4\right)^2}$

Tags

CCSS.HSG.GPE.B.7

The distance formula is another way to write which of the following?

• quadratic formula

• slope formula

• Pythagorean theorem

• none of these answers

Tags

CCSS.HSG.GPE.B.7

6) The ratio is 3:1. How many parts are there?

• 2

• 3

• 4

• 5

Tags

CCSS.6.RP.A.1

CCSS.6.RP.A.2

Directed line segment AB is partitioned by point P into a ratio of 1:3. Which of the following represent this relationship?

• 
• 
• 
• 

Tags

CCSS.HSG.GPE.B.6