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Algebra Unit 7-Part 2 Review

Authored by Colleen Curtis

Mathematics

9th Grade

CCSS covered

Used 2+ times

Algebra Unit 7-Part 2 Review
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given the function  f(x)=5x2x+20f\left(x\right)=-5x^2-x+20 , find  f(3)f\left(3\right) .

-28

-13

62

64

Tags

CCSS.HSF.IF.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The axis of symmetry for a function in the form  f(x)=x2+4x5f\left(x\right)=x^2+4x-5  is  x=2x=-2 . What are the coordinates of the vertex of the graph?

(-9, -2)

(-17, -2)

(-2, -17)

(-2, -9)

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex of the graph of the function  f(x)=x2+8x2f\left(x\right)=x^2+8x-2 ?

(-8, -2)

(-4, -18)

(0, -2)

(-4, 18)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

The function  f(x)=x22x+15f\left(x\right)=-x^2-2x+15 is shown on the graph. What are the domain and range of the function?

The domain is all real numbers. The range is  {y<16}\left\{y<16\right\} .

The domain is all real numbers. The range is  {y16}\left\{y\le16\right\} .

The domain is  {5<x<3}\left\{-5<x<3\right\} . The range is  {y<16}\left\{y<16\right\} .

The domain is  {5x3}\left\{-5\le x\le3\right\} . The range is  {y16}\left\{y\le16\right\} .

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which point is an x-intercept of the quadratic function  f(x)=(x8)(x+9)f\left(x\right)=\left(x-8\right)\left(x+9\right) ?

(0, 8)

(0, -8)

(-8, 0)

(-9, 0)

Tags

CCSS.HSF-IF.C.7A

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which function has an axis of symmetry of  x=2x=-2 ?

 f(x)=(x+2)21f\left(x\right)=\left(x+2\right)^2-1  

 f(x)=(x2)21f\left(x\right)=\left(x-2\right)^2-1  

 f(x)=(x+1)22f\left(x\right)=\left(x+1\right)^2-2  

 f(x)=(x1)2+2f\left(x\right)=\left(x-1\right)^2+2  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the equation of the translated function, g(x)g\left(x\right) , if  f(x)=x2f\left(x\right)=x^2 ?

 g(x)=(x+5)2+2g\left(x\right)=\left(x+5\right)^2+2  

 g(x)=(x+2)2+5g\left(x\right)=\left(x+2\right)^2+5  

 g(x)=(x5)2+2g\left(x\right)=\left(x-5\right)^2+2  

 g(x)=(x2)2+5g\left(x\right)=\left(x-2\right)^2+5  

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