Cramer's Rule & Circles

Solve system by using Cramer's Rule. Answers are written in the following form (x,y)
 $4x+6y=3$  
 $8x-3y=1$  

•  $\left(\frac{1}{4},\frac{1}{3}\right)$  

•  $\left(-\frac{1}{3},\frac{1}{4}\right)$  

•  $\left(\frac{1}{3},\frac{1}{4}\right)$  

•  $\left(\frac{1}{4},-\frac{1}{3}\right)$  

Tags

CCSS.HSA.REI.C.9

Solve system by using Cramer's Rule. Answers are written in the following form (x,y)

 $2x+3y=15$  
 $x-3y=3$  

•  $\left(1,6\right)$  

•  $\left(6,-1\right)$  

•  $\left(6,1\right)$  

•  $\left(-1,6\right)$  

Tags

CCSS.HSA.REI.C.9

Find the determinant of the above matrix.

• -23

• 23

• -7

• 7

What is Dy/D?

• $\frac{-29}{-29}$

• $\frac{-116}{-29}$

• $\frac{29}{-29}$

• $-4$

Tags

CCSS.HSA.REI.C.9

When setting up Cramer's Rule, what is the 2x2 determinant for the numerator for the x in the system?

 

•  $\left|-4\ \ \ -2\right|$  
   $\left|-5\ \ \ -4\right|\$  
  

•  $\left|-4\ \ \ -16\right|$  
   $\left|-5\ \ -26\right|$  
  

•  $\left|-16\ \ \ -2\right|$  
   $\left|-26\ \ \ \ -4\right|$  
  

•  $\left|-4\ \ -4\right|$  
   $\left|-2\ \ -5\right|$  
  

Tags

CCSS.HSA.REI.C.9

When setting up Cramer's Rule, what is the 2x2 determinant for the numerator for the y in the system?

 

•  $\left|-4\ \ \ -2\right|$  
   $\left|-5\ \ \ -4\right|\$  
  

•  $\left|-4\ \ \ -16\right|$  
   $\left|-5\ \ -26\right|$  
  

•  $\left|-16\ \ \ -2\right|$  
   $\left|-26\ \ \ \ -4\right|$  
  

•  $\left|-4\ \ -4\right|$  
   $\left|-2\ \ -5\right|$  
  

Tags

CCSS.HSA.REI.C.9

Use Cramer's Rule to solve the system.

• (1/6, -1/2)

• No unique solution

• (5, -1/7)

• (-7/4, -1/7)

Tags

CCSS.HSA.REI.C.9

Solve the system of equations using Cramer's Rule.

• 
  

  $\left(-2,0\right)$
  

• $\left(1,4\right)$

• $\left(2,6\right)$

• $\left(2,-3\right)$

Tags

CCSS.HSA.REI.C.9

Solve the system of equations using Cramer's Rule.

•  $\left(-3,-1\right)$  

•  $\left(-6,6\right)$  

•  $\left(5,-3\right)$  

•  $\left(2,-6\right)$  

Tags

CCSS.HSA.REI.C.9

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1