A 1 7.11 Test Quadratic Equations

 $x^2+10x=24$  

Solve:

• -12

• 12

• 2

• -2

 $x^2+5=6$  

Solve:

• 11

• 1

• -1

• -11

 $x^2+18x=4x-49$  

Solve:

• 0

• 1

• -7

• 7

 $x^2-6x-23=0$  

Solve:

•  $6+\frac{\sqrt{128}}{4}$  
  

• 0

•  $3+4\sqrt{2}$  
  

•  $3-4\sqrt{2}$  
  

 $x^2-9x=0$  

Solve:

• 0

• 1

• 9

• -9

 $4x^2-24=20x$  

Solve:

• 6

• 1

• -1

• -6

 $5x^2+14x=x+6$  

Solve:

• 0

• -3

• 3

•  $\frac{2}{5}$  

 $2x^2-10x+11=0$  

Solve:

•  $\frac{10+\sqrt{3}}{4}$  
  

•  $\frac{10-\sqrt{3}}{4}$  
  

•  $\frac{5+\sqrt{3}}{2}$  
  

•  $\frac{5-\sqrt{3}}{2}$  

Which Equation has solutions of -2 and 3?

• $y=x^2+x-6$

• $y=x^2-x-6$

• $y=x^2-5x+6$

• $y=x^2+5x+6$

If the area of a rectangle is 39 square feet, and one side length is (x-2) and the other side length is (x+8), what is the value of x?