AP Calculus Review

changes sign

equals zero

goes from negative to positive

goes from positive to negative

[2,8]

[0,5]

[2,5]

[-5,-2]U[0,5]

 $f'\left(x\right)q'\left(x\right)$  

 $f'\left(x\right)q'\left(x\right)+f\left(x\right)q\left(x\right)$  

 $f'\left(q\left(x\right)\right)q'\left(x\right)$  

 $f'\left(x\right)q\left(x\right)+f\left(x\right)q'\left(x\right)$  

Both I and II

I only

II only

Neither I or II

 $-\frac{\sqrt{2}}{2}$  

DNE

 $0$  

 $\frac{\sqrt{2}}{2}$  

 $-\frac{2}{\left(1-2x\right)^2}$  

 $-2\ln\left|1-2x\right|$  

 $\frac{2}{\left(1-2x\right)^2}$  

 $-\frac{1}{2}\ln\left|1-2x\right|$  

$\left|v\left(t\right)\right|=2$

$v\left(t\right)=2$

$a\left(t\right)=2$

$\left|a\left(t\right)\right|=2$

 $\frac{1}{2}\sin\left(2x\right)+3x$  

 $\cos\left(2x\right)$  

 $2\cos\left(2x\right)+3$  

 $\cos\left(2x\right)+3$  

 $-\frac{1}{\sqrt{1-x^2}}$  

 $\frac{1}{\sqrt{1-x^2}}$  

 $-\sin x$  

 $\sin x$  

 $\int_0^2\left(x^2-2x\right)dx$  

 $\int_0^2\left(2x-x^2\right)dx$  

 $\int_0^4\left(2x-x^2\right)dx$  

 $\int_0^4\left(x^2-2x\right)dx$