Simplify $\frac{\text{cot x}}{\text{tan x}}$  

•  $\cos^2x$  

•  $\sin^2x$  

•  $\cot^2x$  

•  $\tan^2x$  

Simplify $\frac{\text{sec x}}{\text{cos x}}-1$  

•  $\cos^2x-1$  

•  $\tan^2x$  

• 0

•  $\sin^2x-1$  

 $\sin^2x+\cos^2x=$  

•  $1$  

•  $-1$  

•  $\tan^2x$  

•  $\cot^2x$  

• csc²θ
• sec²θ
• cscθ
• 1

 Simplify:
 $\sin x\left(\sec x-\csc x\right)$ 

•  $1-\tan x$  

•  $\cot x-1$  

•  $1-\cot x$  

•  $\tan x-1$  

Verify the following.

tanB (cotB + tanB) = sec²B

• Not an identity

• Identity

Which of the following would be a step to prove the following identity?

• (1/ sin x) - (1 / cos x)

• (cos x - sin x) / ( sin x)

• (cos x - sin x) / (cos x)

• (1/ sin x cos x)

If you had to verify:

tanxcotx-cos²x=sin²x,

which side would you begin with?

• The left half - it is more complicated

• The right half - it is simpler

• Either side - it doesn't matter

• HELP...I am clueless. Stop the madness

 $If\ \csc\theta=\frac{12}{7},\ find\ \cos\theta$   $such\ that\ \tan\theta<0$  

• 7/12

• 5/12

• √95/12

• -√95/12

 $Given\ that\ \tan\theta=\frac{9}{13},\ find$   $\sin\theta\ if\ \cos\theta<0$  

•  $\frac{5\sqrt{10}}{13}$  

•  $-\frac{9\sqrt{10}}{50}$  

•  $\frac{13\sqrt{10}}{50}$  

•  $-\frac{5\sqrt{10}}{9}$