Tập nghiệm của bất phương trình: 2 x – 4 > 0 là

S = ( 2 : + ∞ ) S=\left(2:+\infty\right) S = ( 2 : + ∞ )

S = [ 2 ; + ∞ ) S=\left[2;+\infty\right) S = [ 2 ; + ∞ )

Cho cos ⁡ x = − 1 3 ( 90 ° < x < 180 ° ) \cos x=-\frac{1}{3}\left(90\degree<x<180\degree\right) cos x = − 3 1 ( 9 0 ° < x < 1 8 0 ° ) . Tính tan ⁡ x \tan x tan x ?

− 2 2 -2\sqrt{2} − 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 2 2 3 \frac{-2\sqrt{2}}{3} 3 − 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 3 \frac{2\sqrt{2}}{3} 3 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 2 2\sqrt{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Phương trình đường tròn đường kính AB với A(1; 6) và B(-3; 2) là:

x 2 + y 2 + 2 x – 8 y + 9 = 0

x 2 + y 2 + 2 x – 8 y - 15 = 0

Ôn tập Toán 10 học kì 2 (2)

Authored by Le Nhat

Mathematics

10th Grade

Used 64+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính A:

A=-1

A=0

A=2

A=1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Công thức nào sai?

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính A:

A=2

A=1

A=0

A=-1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính $\cos\ \alpha$ :

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tính $\sin\ 2\alpha$ :

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Chọn đáp án bằng:

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Điều kiện xác định của phương trình

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Ôn tập Toán 10 học kì 2 (2)

Tính A:

Công thức nào sai?

Tính A:

Tính $\cos\ \alpha$ :

Tính $\sin\ 2\alpha$ :

Chọn đáp án bằng:

Điều kiện xác định của phương trình

Phương trình có hai nghiệm phân biệt khi

Tìm tọa độ giao điểm của 2 đ.thẳng:
d: x - y - 2= 0
d': x + y - 6= 0

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Ôn tập Toán 10 học kì 2 (2)

Tính A:

Công thức nào sai?

Tính A:

Tính cos⁡ α\cos\ \alphacos α :

Tính sin⁡ 2α\sin\ 2\alphasin 2α :

Chọn đáp án bằng:

Điều kiện xác định của phương trình

Phương trình có hai nghiệm phân biệt khi

Tìm tọa độ giao điểm của 2 đ.thẳng:d: x - y - 2= 0d': x + y - 6= 0

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Tính $\cos\ \alpha$ :

Tính $\sin\ 2\alpha$ :

Tìm tọa độ giao điểm của 2 đ.thẳng:
d: x - y - 2= 0
d': x + y - 6= 0