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10th Grade

6 Qs

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Assessment

Quiz

Mathematics

10th Grade

Medium

Created by

黃筱崴 黃筱崴

Used 4+ times

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6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

abc 分別表△ABC 三內角∠A,∠B,∠C 之對邊長,則△ABC 的面積為何?

12bcsinA\frac{1}{2}bc\sin A

12acsinB\frac{1}{2}ac\sin B

12absinC\frac{1}{2}ab\sin C

以上皆是

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

abc 分別表△ABC 三內角∠A,∠B,∠C 之對邊長,而R 表其外接圓半徑,則正弦定理為何?

asinB=bsinC=csinA=2R\frac{a}{\sin B}=\frac{b}{\sin C}=\frac{c}{\sin A}=2R

bsinA=csinB=asinC=12R\frac{b}{\sin A}=\frac{c}{\sin B}=\frac{a}{\sin C}=\frac{1}{2R}

asinA=bsinB=csinC=2R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R

asinA=bsinB=csinC=12R\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{1}{2R}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

abc 分別表△ABC 三內角∠A,∠B,∠C 之對邊長,則餘弦定理為何?

a2=b2+c22bccosAa^2=b^2+c^2-2bc\cos A

b2=a2+c22accosBb^2=a^2+c^2-2ac\cos B

c2=a2+b22abcosCc^2=a^2+b^2-2ab\cos C

以上皆正確

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A 為銳角 (cos A>0) 等價於下列何者?

a2b2c2

a2b2c2

a2b2c2

以上皆可

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 (海龍公式)設△ABC三邊長為a,b,c,且 

 s=\frac{a+b+c}{2} 

(半周長),則△ABC 的面積為何?

 (sa)(sb)(sc)\sqrt{\left(s-a\right)\left(s-b\right)\left(s-c\right)}  

 s(sa)(sb)(sc)\sqrt{s\left(s-a\right)\left(s-b\right)\left(s-c\right)}   

 s(sa)(sb)(sc)s\sqrt{\left(s-a\right)\left(s-b\right)\left(s-c\right)}  

以上皆可

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

若直線與 x 軸的正方向夾角為θ,(-90°<θ≤ 90°),稱為此直線的斜角。若直線的斜率為 m,則 m

sinθ\sin\theta

cosθ\cos\theta

tanθ\tan\theta

sinθcosθ\sin\theta\cos\theta