Day 9 Equations and Inequalities Review

Answer explanation

To solve the equation 3x - 4 = 11, first add 4 to both sides to get 3x = 15. Then divide by 3 to find x = 5. Therefore, the correct answer is x = 5.

Tags

CCSS.7.EE.B.4A

Answer explanation

To simplify the expression, distribute 6 to both terms inside the parentheses: 6*3x + 6*5 = 18x + 30. Then divide by 2 to get 9x + 15.

Tags

CCSS.6.EE.A.3

Answer explanation

To solve the equation, first distribute the 3/4 to get 3/4x - 3/2 = 15. Then, add 3/2 to both sides to isolate x, giving x = 22. Therefore, the correct answer is x = 22.

Tags

CCSS.7.EE.B.4A

Answer explanation

To solve the inequality 11z - 43 < -32, add 43 to both sides to get 11z < 11. Then, divide by 11 to find z < 1. Therefore, the correct answer is z < 1.

Tags

CCSS.7.EE.B.4B

Answer explanation

To solve for W, isolate it in the equation. Start by subtracting 2L from both sides to get P-2L=2W. Then divide by 2 to get W=(P-2L)/2.

Tags

CCSS.HSA.CED.A.4

• m = -2

• m = -10

• m = 5

• m = 0

Answer explanation

To solve the equation, combine like terms: 5m + 3m = -20 + 4. This simplifies to 8m = -16. Dividing by 8 gives m = -2, which is the correct answer.

Answer explanation

To solve the inequality, first multiply both sides by 3 to get 2(y-3) < -54. Then distribute to get 2y - 6 < -54. Add 6 to both sides to get 2y < -48. Finally, divide by 2 to get y < -24, which is the correct choice.

Tags

CCSS.7.EE.B.4B

Answer explanation

To solve the inequality 5-4x ≥ 29, first subtract 5 from both sides to get -4x ≥ 24. Then, divide by -4 to find x ≤ -6.

Tags

CCSS.7.EE.B.4B

Answer explanation

To solve for b1, isolate it on one side of the equation. Start by multiplying both sides by 2 to get rid of the fraction: 2A = h(b1 + b2). Then, subtract b2 and divide by h to solve for b1: b1 = (2A - b2) / h.

Tags

CCSS.HSA.CED.A.4

• The number of books in Darren's collection

• The number of magazines in Darren's collection

• The total value of Darren's collection

• The total weight of Darren's collection

Answer explanation

A represents the total value of Darren's collection calculated by multiplying the number of books by $10 each and the number of magazines by $5 each.

Tags

CCSS.HSA-SSE.A.1A