Basic Differentiation Rules

Basic Differentiation Rules

11th Grade

20 Qs

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Basic Differentiation Rules

Basic Differentiation Rules

Assessment

Quiz

Mathematics

11th Grade

Medium

CCSS
HSF-BF.A.1A

Standards-aligned

Created by

Bian Camille Patano

Used 8+ times

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20 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given  f(x)=3x2+2x1f\left(x\right)=3x^2+2x-1  , which of the following is the correct derivative?

 f(x)=6x2+2f'\left(x\right)=6x^2+2  

 f(x)=6x+2f'\left(x\right)=6x+2  

 f(x)=6x2+2f'\left(x\right)=6x^2+2  

 f(x)=6x2+2x2xf'\left(x\right)=6x^2+2x^2-x  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is the correct definition of the Power Rule of derivatives?

Given f(x)=xnf\left(x\right)=x^n , f(x)=xn1f'\left(x\right)=x^{n-1}

Given f\left(x\right)=x^n , f(x)=nxn1f'\left(x\right)=nx^{n-1}

Given f\left(x\right)=x^n , f(x)=xn1nf'\left(x\right)=\frac{x^{n-1}}{n}

Given f\left(x\right)=x^n , f(x)=nxn1f'\left(x\right)=\frac{n}{x^{n-1}}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given f(x)=17f\left(x\right)=17  , what is the derivative of  f(x)f\left(x\right)  ?

 f(x)=17xf'\left(x\right)=17x  

 f(x)=17f'\left(x\right)=17  

 f(x)=0f'\left(x\right)=0  

 f(x)=17x2f'\left(x\right)=17x^2  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given f(x)=3xf\left(x\right)=3x  , which of the following is the derivative of the function?

 h(x)=3h'\left(x\right)=3  

 q(x)=3q'\left(x\right)=3  

 b(x)=3b'\left(x\right)=3  

 f(x)=3f'\left(x\right)=3  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of 0?

You can't take the derivative of 0.

0

This is all derivative.

Any constant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Differentiate with respect to x. y=1x3y=\frac{1}{x^3}  


 yx=1x4\frac{\partial y}{\partial x}=\frac{1}{x^4}  

 yx=3x\frac{\partial y}{\partial x}=-3x  

 yx=3x3\frac{\partial y}{\partial x}=-\frac{3}{x^3}  

 yx=3x4\frac{\partial y}{\partial x}=-\frac{3}{x^4}  

Tags

CCSS.HSF-BF.A.1A

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find dydx\frac{dy}{dx}  for y=x8+2x6x34xy=x^8+2x^6-x^3-4x  


 dydx=8x712x53x24x\frac{dy}{dx}=8x^7-12x^5-3x^2-4x  

 dydx=8x7+12x53x24\frac{dy}{dx}=8x^7+12x^5-3x^2-4  

 dydx=8x7+12x5+3x2+4x\frac{dy}{dx}=8x^7+12x^5+3x^2+4x  

 dydx=8x712x5+3x2+4\frac{dy}{dx}=8x^7-12x^5+3x^2+4  

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