CALCULANDO - FINAL

 $120\div\left\{560\div\left[40+\left(300\div10\right)\right]\ +\ 12\right\}=$  

 $64\div\left\{2\times\left[7+18\div\left(3+15\right)\right]\right\}+7\times3-18\div3=$  

 $360\div\left\{100-\left[50-\left(2\times3+4\right)\right]\right\}+20=$  

 $\left(64\div8-2\times3\right)\times10=$  

 $33\div\left\{10+\left[6\div3+\left(1+2\right)\right]-4\right\}\ =$  

 $2\times\left(7+1\right)-32\div\left(7+9\right)=$  

 $7+\left(8+3\right)-30\div\left(9+6\right)=$