Solving Equations

You want to solve for x. Which of these is the correct "step 1"?

• $\log_78=\log_7x$

• $\log_742=\log_7x$

• $\log_748=\log_7\left(\frac{x}{6}\right)$

• $\log_754=\log_7x$

Finish solving for x

• x = 6

• x = 7

• x = 8

• x = 56

We want to solve for x. What's the first step?

• Rewrite as a logarithm: $\log_{189}3=x$

• Rewrite as a logarithm: $\log_3189=x$

• Rewrite 189 with a base of 3: $3^x=3^{63}$

• Rewrite 189 with a base of 3: $3^x=3^9$

Solve for x.
 $2\log_410=\log_4\left(8x\right)+\log_4\left(5\right)$  

• x = 2.5

• x = 0.5

• x = 1.538

• x = 11.875

log_x1000=3

• 1

• 10

• 30

• 3

log₄(3x-1)=log₄(2x+3)

• 4

• 3

• 1

• 8

Log with a base "e" (log_e) is the same thing as...

• "e"
• Natural Logarithm (LN)
• Common Logarithm (Log)
• Natural Log, base "e"
  LN_e

Change to Logarithmic Form:
5³ = 125

• log ₅ 125 = 3
• log ₃ 125 = 5
• log ₅ 3 =125
• log₁₂₅ 3 = 5

lnx = -3

• 8.1548

• -8.1548

• 0.0498

• -0.0498

Solve for x:

2^{3x - 1} = 32

• 0

• -1

• 5/3

• 2