solving by factoring

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

Solve the equation by factoring:

x² - 6x = -8

• x=2 and x=4

• x= -2 and x= -4

• x= -2 and x=4

• x=2 and x= -4

Factor and Solve

 $x^2-2x-35=0$  

•  $x=\ +7,\ -8$  

•  $x=+7,\ -5$  

•  $x=-5,\ +7$  

•  $x=8$  

What are the two solutions to this quadratic that is already factored for you.

 $\left(3x+4\right)\left(x-9\right)=0$  

•  $x=-9,-4$  

•  $x=+\frac{4}{3},-9$  

•  $x=-\frac{4}{3},+9$  

•  $x=+3,+4$  

Solve for the values of x:
(2x - 1)(x + 4) = 0

• { 1/2, -4 }
•  { 1/2, 4 }
• { 2, -4 }
• { -2, 4 }

 $\left(7f-3\right)\left(9f+1\right)=0$  

•  $f=\frac{3}{7},\ f=-\frac{1}{9}$  

•  $f=-\frac{3}{7},\ f=\frac{1}{9}$  

•  $f=\frac{3}{7,}\ f=\frac{1}{9}$  

•  $f=-\frac{3}{7},\ f=-\frac{1}{9}$  

Which equation is the standard form of a quadratic function?

• f(x) = mx + b

• f(x) = a(x - m)(x - n)

• f(x) = ax² + bx + c

• f(x) = a(x - h)² + k

Solve for the values of x:

(2x + 5)(5x - 2) = 0

• x= -5/2, x= -2/5

• x= -5/2, x= 2/5

• x= 5/2, x= 2/5

• x= 5/2, x= -2/5

Solve
 2x² - 3x - 2 = 0

• x = 1, x = -1
• x = -1/2, x = 2
• x = 1/2, x = 2
• x = 1/2, x = 1

Solve by factoring: x² = 9x - 20

• x = -4 and x = -5

• x = 20 and x = -9

• x = 4 and x = 5

• x = -4 and x = 5