1.03 solving radical equations (alg2)

 $\sqrt{2x+1}=3$  

• x=4, solution is extraneous

• x=4, solution is not extraneous

• x=5, solution is extraneous

• x=5, solution is not extraneous

Given the equation  $2\sqrt{x-5}=2$  , solve for x and identify if it is an extraneous solution.

• x=6, solution is not extraneous

• x=6, solution is extraneous

• x=11, solution is not extraneous

• x=11, solution is extraneous

Solve for x, given the equation  $\sqrt{x-5}+7=11.$  

• x=21, solution is not extraneous

• x=21, solution is not extraneous

• x=81, solution is extraneous

• x=81, solution is not extraneous

Charlie was carrying around the steps to solve  $\sqrt{6x+4}=8.$  On his way through the Math Factory, Charlie dropped them and they mixed with other steps. Put the correct steps in order to solve  $\sqrt{6x+4}=8.$  

• First A, then F, then E

• First B, then D, then C

• First D, then C, then F

• First F, then D, then C