Electric potential and capacitors -DPP5(ISC)

Electric potential and capacitors -DPP5(ISC)

12th Grade - University

10 Qs

quiz-placeholder

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Electric potential and capacitors -DPP5(ISC)

Electric potential and capacitors -DPP5(ISC)

Assessment

Quiz

Physics

12th Grade - University

Hard

Created by

salman undefined

Used 6+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Inside a hollow charged spherical conductor, the potential

Q2-\frac{Q}{2}

Q4-\frac{Q}{4}

+Q2+\frac{Q}{2}

+Q4+\frac{Q}{4}

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Two equal charges q are placed at a distance of 2a and a third charge -2q is placed at the midpoint. The potential energy of the system is

q28πϵoa\frac{q^2}{8\pi\epsilon_oa}

6q28πϵoa\frac{6q^2}{8\pi\epsilon_oa}

7q28πϵoa\frac{-7q^2}{8\pi\epsilon_oa}

9q28πϵoa\frac{9q^2}{8\pi\epsilon_oa}

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If a charged spherical conductor of radius 10cm has potential at a point distant 5cm from its centre, then the potential at a point distant 15cm from the centre will be

13 V\frac{1}{3\ }V

23 V\frac{2}{3\ }V

32V\frac{3}{2}V

3V3V

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

As shown in the figure, charges +q and -q are placed at the vertices B and C of an isosceles triangle. The potential at the vertex A is

14πϵo2qa2+b2\frac{1}{4\pi\epsilon_o}\frac{2q}{\sqrt{a^2+b^2}}

zero

14πϵoqa2+b2\frac{1}{4\pi\epsilon_o}\frac{q}{\sqrt{a^2+b^2}}

14πϵoqa2+b2\frac{1}{4\pi\epsilon_o}\frac{-q}{\sqrt{a^2+b^2}}

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

An electron of mass and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

VemV\sqrt{\frac{e}{m}}

Vem\sqrt{\frac{Ve}{m}}

2Vem\sqrt{\frac{2Ve}{m}}

2Vem\frac{2Ve}{m}

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The radius of a soap bubble whose potential is 16V is doubled. The new potential of the bubble will be

2V

4V

8V

16V

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

A proton is about 1840 times heavier than an electron. When it is accelerated by a potential difference of 1 kV, its kinetic energy will be

1840 keV

1/1840 keV

1 keV

920 keV

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