Linear Algebra Unit 1 Summative Review

33 = 4a - 7

• a=-10
• a=10
• a=4.5

Tags

CCSS.7.EE.B.4A

6 - 3a = 21

• a= 9
• a= -9
• a= -5
• a= 5

Tags

CCSS.7.EE.B.4A

3 + (¹∕₄)a = 31

• a= 28
• a= 112
• a= 7
• a= 67

Tags

CCSS.7.EE.B.4A

7 + ^a⁄₃ = 5

• a= -2
• a= -6
• a= 3
• a= 15

Tags

CCSS.7.NS.A.1B

^{(a + 3)}⁄₇ = 3

• a= 18
• a= 21
• a= 4
• a= 11

Tags

CCSS.7.EE.B.4A

-15 = 5a +12- 2a + 6

• -11
• -3
• 10
• 7

Tags

CCSS.8.EE.C.7B

What is the first step in solving the equation 2a - 4(a - 5) = 10

• Add 4 to both sides
• Add the 2a and a 
• Distribute 4 to a and -5
• Distribute -4 to a and -5

Tags

CCSS.8.EE.C.7B

4(a + 3) = -32

• -11
• -44
• -20
• -8

Tags

CCSS.7.EE.B.4A

8 = (³⁄₄)a +12 - a + 4

• 32
• -6
• -4
• 4

Tags

CCSS.8.EE.C.7B

22 + 2a = 37 + 6 + a

• 21
• -21
• 5
• 6