ADDMATH : F5 - BAB 2 DIFFERENTIATION

 $\lim_{x\rightarrow0}\ \left(1-x^2\right)$  

• 1

• 2

• 0

•  $\frac{1}{2}$  

 $\lim_{x\rightarrow\infty}\ \frac{-9-x^2}{x^2}$  

• 9

• 1

• -9

• -1

 $\lim_{x\rightarrow1}\left(\frac{x^2+5x-6}{x-1}\right)$  

• 7

• -7

• 0

• 1

Differentiate $f\left(x\right)=\frac{7}{\left(3-2x\right)^3}$  

•  $f'\left(x\right)=\frac{42}{\left(3-2x\right)^4}$  

•  $f'\left(x\right)=\frac{21}{\left(3-2x\right)^4}$  

•  $f'\left(x\right)=\frac{42}{\left(3-2x\right)^2}$  

•  $f'\left(x\right)=\frac{21}{\left(3-2x\right)^2}$  

differentiate $y=\frac{x^3+8x^2-9}{x}$  

•  $\frac{\text{d}x}{\text{d}y}=\frac{2x^3+8x^2+9}{x^2}$  

•  $\frac{\text{d}x}{\text{d}y}=\frac{2x^3+8x^2+9}{x^{ }}$  

•  $\frac{\text{d}x}{\text{d}y}=\frac{2x^3+8x^2}{x^2}$  

•  $\frac{\text{d}x}{\text{d}y}=\frac{2x^3+8x^2}{x^{ }}$  

Given $y=2x^2+5$ , find the gradient of tangent at point (1,7) 

Diberi $y=2x^2+5$ , cari kecerunan tangen pada titik (1,7) 

• 1

• 3

• 2

• 4

Given $y=2x^2+5$ , find the gradient of normal at point (1,7) 

Diberi $y=2x^2+5$ , cari kecerunan normal pada titik (1,7)

•  $-\frac{1}{4}$  

•  $\frac{1}{4}$  

•  $4$  

•  $-4$  

Given $y=\frac{x}{2x+7}$ , find the equation of normal at point (0,3) 

•  $y=7x+3$  

•  $y=-7x+3$  

•  $y=\frac{1}{7}x+3$  

•  $y=-\frac{1}{7}x+3$  

Find the coordinate of turning point for equation $y=4+8x-x^2$  and determine whether the point is a maximum point, minimum point or an inflection point

cari koordinat titik pusingan untuk persamaan  $y=4+8x-x^2$  dan tentukan sama ada titik tersebut merupakan titik maksimum, minimum atau lengkok balas

• turning point (4,20) , maximum point

• turning point (4,20) , minimum point

• turning point (4,0) , maximum point

• turning point (4,0) , minimum point