Diketahui bidang empat T. ABC seperti pada gambar berikut! alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = 3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik B ke C adalah ....

6 \sqrt{6} 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cm

2 2 2\sqrt{2} 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cm

10 \sqrt{10} 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cm

2 3 2\sqrt{3} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cm

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = 3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik T ke D adalah

42 2 c m \frac{\sqrt{42}}{2}cm 2 4 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

45 2 c m \frac{\sqrt{45}}{2}cm 2 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

45 3 c m \frac{\sqrt{45}}{3}cm 3 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

42 3 c m \frac{\sqrt{42}}{3}cm 3 4 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

45 4 c m \frac{\sqrt{45}}{4}cm 4 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

pada limas beraturan T. ABCD panjang rusuk tegak 25 cm dan panjang rusuk alasnya 7 2 c m 7\sqrt{2}\ cm 7 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m jarak titik T kebidang ABCD adalah ...

12 2 c m 12\sqrt{2}\ cm 1 2 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

12 3 12\sqrt{3} 1 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

24 2 c m 24\sqrt{2}\ cm 2 4 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> c m

PTS GANJIL BANGUN RUANG

Authored by Yeyet Melawati

Mathematics

12th Grade

Used 15+ times

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15 questions

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MULTIPLE CHOICE QUESTION

5 mins • 5 pts

jika dua buah garis tidak dapat dibuat suatu bidang datar maka dinyatakan garis ....

Tegak lurus

Berpotongan

Sejajar

Bersilangan

Berhimpit

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

Diketahui kubus ABCD EFGH, titik P merupakan titik potong diagonal bidang atas, dengan panjang rusuk 6 cm. tan sudut antara garis PB dengan ABCD adalah ...

√2

₂ √2

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

diketahui kubus ABCD EFGH, rusuk-rusuknya 10 cm . jika jarak dari titik F ke AC adalah ...

$\sqrt{6}$

$5\sqrt{2}$

$5\sqrt{6}$

$10\sqrt{2}\$

$10\sqrt{6}$

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

Diketahui kubus ABCD EFGH jarak antara titik C ke bidang BDG yang panjang rusuknya 6 adalah ...

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

balok ABCD EFGH mempunyai panjang 4 cm, lebar 2 cm dan tinggi 3 cm. jarak antara BC dan EH adalah ....

$\sqrt{13}$ cm

$2\sqrt{5}$ cm

5 cm

6 cm

$5\sqrt{2}$ cm

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

balok ABCD EFGH mempunyai panjang AB 4 cm, BC 2 cm dan BF 3 cm, jarak antara BE dengan bidang CDHG adalah ...

$5\sqrt{2}$

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

balok ABCD EFGH mempunyai panjang 4 cm lebar 2 cm dan tinggi 3 cm jatak antara bidang ACBD dengan bidang EFGH adalah ....

2 cm

3 cm

4 cm

5 cm

$5\sqrt{2}$

MULTIPLE CHOICE QUESTION

10 mins • 5 pts

Diketahui bidang empat T. ABC seperti pada gambar berikut!

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = $\sqrt{3}$ titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik B ke C adalah ....

$\sqrt{6}$ cm

$2\sqrt{2}$ cm

$\sqrt{10}$ cm

$2\sqrt{3}$ cm

4 cm

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = $\sqrt{3}$
titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik T ke D adalah

$\frac{\sqrt{45}}{2}cm$

$\frac{\sqrt{42}}{2}cm$

$\frac{\sqrt{45}}{3}cm$

$\frac{\sqrt{42}}{3}cm$

$\frac{\sqrt{45}}{4}cm$

10.

MULTIPLE CHOICE QUESTION

5 mins • 5 pts

pada limas beraturan T. ABCD panjang rusuk tegak 25 cm dan panjang rusuk alasnya $7\sqrt{2}\ cm$
jarak titik T kebidang ABCD adalah ...

12 cm

$12\sqrt{2}\ cm$

$12\sqrt{3}$

24 cm

$24\sqrt{2}\ cm$

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PTS GANJIL BANGUN RUANG

jika dua buah garis tidak dapat dibuat suatu bidang datar maka dinyatakan garis ....

Diketahui kubus ABCD EFGH, titik P merupakan titik potong diagonal bidang atas, dengan panjang rusuk 6 cm. tan sudut antara garis PB dengan ABCD adalah ...

diketahui kubus ABCD EFGH, rusuk-rusuknya 10 cm . jika jarak dari titik F ke AC adalah ...

Diketahui kubus ABCD EFGH jarak antara titik C ke bidang BDG yang panjang rusuknya 6 adalah ...

balok ABCD EFGH mempunyai panjang 4 cm, lebar 2 cm dan tinggi 3 cm. jarak antara BC dan EH adalah ....

balok ABCD EFGH mempunyai panjang AB 4 cm, BC 2 cm dan BF 3 cm, jarak antara BE dengan bidang CDHG adalah ...

balok ABCD EFGH mempunyai panjang 4 cm lebar 2 cm dan tinggi 3 cm jatak antara bidang ACBD dengan bidang EFGH adalah ....

Diketahui bidang empat T. ABC seperti pada gambar berikut!alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = 3\sqrt{3}3​ titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik B ke C adalah ....

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = 3\sqrt{3}3​ titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik T ke D adalah

pada limas beraturan T. ABCD panjang rusuk tegak 25 cm dan panjang rusuk alasnya 72 cm7\sqrt{2}\ cm72​ cm jarak titik T kebidang ABCD adalah ...

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Discover more resources for Mathematics

Diketahui bidang empat T. ABC seperti pada gambar berikut!

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = $\sqrt{3}$ titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik B ke C adalah ....

alas ABC merupakan segi tiga sama kaki siku - siku di A, dengan AB = AC = $\sqrt{3}$
titik T tegak lurus pada bidang ABC, dengan TA = 3. jarak dari titik T ke D adalah

pada limas beraturan T. ABCD panjang rusuk tegak 25 cm dan panjang rusuk alasnya $7\sqrt{2}\ cm$
jarak titik T kebidang ABCD adalah ...