Graphing Motion - Analyze and Interpret

What is the object doing between 0 s and 2 s.

• not moving

• moving towards the reference point

• moving away from the reference point

Answer explanation

The object is moving away as its displacement or how far it has changed position is increasing.

Tags

NGSS.MS-PS3-1

What is the object doing between 0 s and 2 s.

• not moving

• moving towards the reference point

• moving away from the reference point

Answer explanation

The object is moving away as its displacement or how far it has changed position is increasing.

What is the object doing between 2 s and 4 s.

• not moving

• moving towards the reference point

• moving away from the reference point

Answer explanation

The object is moving towards its reference point as the displacement is decreasing between 4 and 5 seconds.

Tags

NGSS.MS-PS3-1

Which analysis statement(s) are correct for this graph?

• As the time increased from 0 s to 2 s the displacement increased between 0 m and 2 m.

Answer explanation

On the displacement-time graph between 0s and 2s...

the displacement increases from 0m to 4 m

the velocity is

4m - 0m = 4m = 2 m

2 s - 0 s 2 s s

the acceleration is 0 m/s2 as the slope of the line does not change.

What is the velocity shown by the graph?

Answer explanation

The object moves 4.5 m in 9 seconds. Velocity is the slope of a displacement -time graph.

v = 4.5m - 0m = 4.5m = 0.5 m

9 s - 0 s 9 s s

Tags

NGSS.MS-PS3-1

What equation matches this graph?

• d = 0.5t

• d = 1t

• d = 2t

Answer explanation

Find the slope of the graph.

v = 4.5m - 0m = 4.5m= 0.5 m

9 s - 0 s 9 s s

Check equation d = 0.5(t)

0 m = 0.5m/s(0s)

1.5 m = 0.5m/s(3s)

3 m = 0.5m/s(6s)

4.5 m = 0.5m/s(9s)

Tags

equation

How far did the object travel in 6 seconds?

Answer explanation

Look at the velocity-time graph. Find 3 seconds on time(s) axis. It is on the bottom of the graph. Go up until you meet the line. Next, go to the left until you meet the dependent variable, displacement(m). This is the displacement is 3 meters.

What would be a correct analysis statement between 0 s and 3 s?

"As the time increased from 0 s to 3 s ..."

Answer explanation

On the velocity-time graph..

The velocity increases from 0 m/s to 3 m/s.

The line is straight so it is linear.

Acceleration is the slope of a line on a velocity-time graph.

a = 3m/s - 0m/s = 3m/s2

3 s - 0 s

Tags

NGSS.MS-PS3-1

What would be a correct analysis statement between 0 s and 3 s?

"As the time increased from 0 s to 3 s ..."

• the displacement increased linearly from 0 m to 1.5 m.

• the displacement increased nonlinearly from 0 m to 3 m.

• the displacement increased linearly from 0 m to 5 m.

Answer explanation

FInd the time axis at the bottom.

Find 3 s.

Move up until you reach the line.

Move left until you reach the displacement(m) axis.

The displacement is 1.5 m.

What equation matches this graph?

• v= 0.5t

• v = 1t

• v = 2t

Answer explanation

The equation is the slope of the line.

Tags

equation