Quiz about Y9 Online Assessment Final Revision

Question 1

Given that 2x = 9 - (5x - 12),

find the value of x.

Accepted Answer

3

Answer

$$-\frac{3}{7}$$

Answer

-1

Answer

1

Question 2

5t + 10 - st - 2s =

Accepted Answer

(t + 2)(5 - s)

Answer

(t - 2)(s - 5)

Answer

(5 - st)(5 - s)

Answer

(5 - s)(t - 2)

Question 3

6(x - 3y) - 4(3x - 5y) =

Accepted Answer

-6x + 2y

Answer

18x + 38y

Answer

6x - 2y

Answer

-6x + 38y

Question 4

Solve

$$\frac{m}{4}+1=\frac{3m}{4}-3$$

Accepted Answer

m = 8

Answer

m = -8

Answer

m = 4

Answer

m = -4

Question 5

The age of Mr Sham is thrice the age of his youngest son.

Their total age is 80 years.

Find the age of his youngest son.

Accepted Answer

20 years

Answer

25 years

Answer

35 years

Answer

60 years

Question 6

Solve the simultaneous linear equations.

7a - 3b = 15

a + 2b = 7

Accepted Answer

a = 3, b = 2

Answer

$$a=-\frac{9}{11},\ b=-\frac{34}{11}$$

Answer

$$a=\frac{9}{11},\ b=\frac{34}{11}$$

Answer

a = -3, b = -2

Question 7

One book and four pens cost $30.

With the same amount of money, I can buy two books and two pens.

How much does each pen cost?

Accepted Answer

$5

Answer

$7

Answer

$8

Answer

$10

Question 8

It is given that $$S=\frac{n\left(a+l\right)}{2}$$

Find the value of S when n = 20, a = -5 and l = 17.

Accepted Answer

120

Answer

106

Answer

220

Answer

1006

Question 9

Given that $$\sqrt[3]{\frac{7m-n}{4}}=3$$ .

Express m in terms of n.

Accepted Answer

$$\frac{108+n}{7}$$

Answer

$$\left(\frac{12+k}{7}\right)^3$$

Answer

$$\frac{36+n}{7}$$

Answer

$$\frac{4\left(3+n\right)}{7}$$

Question 10

$$\frac{8}{2ab}-\frac{3}{a^2c}=$$

Accepted Answer

$$\frac{4ac-3b}{a^2bc}$$

Answer

$$\frac{5}{2abc}$$

Answer

$$\frac{4c-6b}{abc}$$

Answer

$$\frac{8a^2c-6ab}{2abc}$$

Question 11

f(x) = 10 - 3x

Evaluate f(-2).

Accepted Answer

16

Answer

4

Answer

15

Answer

42

Question 12

f(x) = 2x - 5

Find $$f^{-1}\left(x\right)$$ .

Accepted Answer

$$\frac{x+5}{2}$$

Answer

2x + 5

Answer

$$-\frac{5+x}{2}$$

Answer

5 - 2x

Question 13

Solve

$$4x^2-19x+12=0$$

Accepted Answer

$$x=\frac{3}{4},\ 4$$

Answer

$$x=-\frac{3}{2},\ -2$$

Answer

$$x=\frac{3}{2},\ -2$$

Answer

$$x=-\frac{3}{4},\ -4$$

Question 14

The table shows the relation between variables x and y.

Given that y varies directly as the square root of x, calculate the value of b.

Accepted Answer

64

Answer

1

Answer

16

Answer

256

Question 15

Given that p is inversely proportional to q and that p = 20 when q = 2,

find the value of p when q = 8

Accepted Answer

5

Answer

1.25

Answer

10

Answer

80

Question 16

A map has a scale of 1:50 000.

What is the length on the ground represented by 2.5 cm on the map?

Accepted Answer

125 000 cm

Answer

20 000 cm

Answer

20 000 km

Answer

125 000 km

Question 17

Express as a single fraction in its simplest form.

$$\frac{5}{m+5}-\frac{2}{m-9}$$

Accepted Answer

$$\frac{3m-55}{\left(m+5\right)\left(m-9\right)}$$

Answer

$$\frac{3}{\left(m+5\right)\left(m-9\right)}$$

Answer

$$\frac{3m+4}{\left(m+5\right)\left(m-9\right)}$$

Answer

$$\frac{3m}{\left(m+5\right)\left(m-9\right)}$$

Question 18

Simplify

$$\frac{3x-6}{x^2-3x+2}$$

Accepted Answer

$$\frac{3}{x-1}$$

Answer

$$\frac{6}{x^2-2}$$

Answer

$$\frac{3}{x^2-1}$$

Answer

$$\frac{3}{\left(x+1\right)\left(x-1\right)}$$

Question 19

The two containers shown in the diagram are geometrically similar.

Their heights are 20 cm and 30 cm.

The diameter of the base of the larger container is 12 cm.

Calculate the diameter of the base of the smaller container.

Accepted Answer

8 cm

Answer

16 cm

Answer

6 cm

Answer

18 cm

Question 20

The two containers shown in the diagram are geometrically similar.

Their heights are 20 cm and 30 cm.

The containers are completely filled with sand.

Given that the smaller container holds 2.4 kg of sand, find the mass of sand the larger container holds.

Accepted Answer

8.1 kg

Answer

5.4 kg

Answer

3.6 kg

Answer

7.4 kg

Question 21

Simplify

$$\frac{8a}{b^3}\div\frac{4a^3c}{3ab}$$

Accepted Answer

$$\frac{6}{ab^2c}$$

Answer

$$6a^2bc$$

Answer

$$\frac{2}{3a^2bc}$$

Answer

$$\frac{2}{3}a^2bc$$

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