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Setting up algebra for parallel lines with a transversal

Authored by C. Swain

Mathematics

8th - 12th Grade

CCSS covered

Used 18+ times

Setting up algebra for parallel lines with a transversal
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20 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m4 = 9x  45m\angle4\ =\ 9x\ -\ 45  What would your equation look like to solve for x?

3x + 9 = 9x - 45

3x + 9 + 9x - 45 = 180

3x + 9 - (9x - 45) = 180

None of the above

Tags

CCSS.7.G.B.5

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m5 = 2x + 23m\angle5\ =\ 2x\ +\ 23  What would your equation look like to solve for x?

3x + 9 = 2x + 23

3x + 9 + 2x + 23 = 180

3x + 9 - (2x + 23) = 180

None of the above

Tags

CCSS.7.G.B.5

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m6 = x + 55m\angle6\ =\ x\ +\ 55  What would your equation look like to solve for x?

3x + 9 = x + 55

3x + 9 + x + 55 = 180

3x + 9 - (x + 55) = 180

None of the above

Tags

CCSS.7.G.B.5

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m8 = 4x 12m\angle8\ =\ 4x\ -12  What would your equation look like to solve for x?

3x + 9 = 4x - 12

3x + 9 + 4x - 12 = 180

3x + 9 - (4x - 12) = 180

None of the above

Tags

CCSS.7.G.B.5

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m7 = 6x  30m\angle7\ =\ 6x\ -\ 30  What would your equation look like to solve for x?

3x + 9 = 6x - 30

3x + 9 + 6x - 30 = 180

3x + 9 - (6x - 30) = 180

None of the above

Tags

CCSS.7.G.B.5

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

If m1 = 3x + 9 m\angle1\ =\ 3x\ +\ 9\   and the  m3 = 5x  18m\angle3\ =\ 5x\ -\ 18  What would your equation look like to solve for x?

3x + 9 = 5x - 18

3x + 9 + 5x - 18 = 180

3x + 9 - (5x - 18) = 180

None of the above

Tags

CCSS.8.G.A.5

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

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If m8 = 4x 12m\angle8\ =\ 4x\ -12 and  m4 = 3x + 2m\angle4\ =\ 3x\ +\ 2   What would your equation look like to solve for x?

4x - 12 = 3x + 2

4x - 12 + 3x + 2= 180

4x - 12 - (3x + 2) = 180

None of the above

Tags

CCSS.8.G.A.5

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